Print with your own font using Python

Given a word or name, the task is to print it in a custom-designed font using Python. Each character of the input is mapped to a pattern made of symbols, allowing you to print text in your own creative style. For example:

Input: ROOT
Output:
..######..
..#....#..
..#.##...
..#...#...
..#....#..
..######..
..#....#..
..#....#..
..#....#..
..######..

Explanation: Each character of "ROOT" is matched with its ASCII-art pattern and printed line by line.

Now, let’s explore different methods to print custom fonts using Python.

Using Pre-Structured ASCII Rows

This method stores every character’s ASCII-art as a list of rows, enabling clean horizontal alignment. It prints the custom font by assembling the output row by row, which looks neat and scales well.

font = { "G":["..######..","..#.......","..#.####..","..#....#..","..#####..."],
         "E":["..######..","..#.......","..#####...","..#.......","..######.."],
         "K":["..#...#...","..#..#....","..##......","..#..#....","..#...#..."] }

name = "GEEK"
rows = len(next(iter(font.values())))
for i in range(rows):
    for ch in name:
        print(font[ch][i], end=" ")
    print()

Output:

..######.. ..######.. ..######.. ..#...#...

..#....... ..#....... ..#....... ..#..#....

..#.####.. ..#####... ..#####... ..##......

..#....#.. ..#....... ..#....... ..#..#....

..#####... ..######.. ..######.. ..#...#...

Explanation:

• font = {...} font maps each letter to a list of strings, one string per row.
• rows = len(next(iter(font.values()))) finds number of rows per letter.
• for i in range(rows): loop over row index (print row 0 for all letters, then row 1, ...).
• for ch in name: loop over letters in the word.
• print(font[ch][i], end=" ") print the i-th row of the letter with a space after it.

Using Dictionary Mapping

This method stores each character as a full block string. It prints each block as soon as the character appears.

font = { "G":"..######..\n..#.......\n..#.####..\n..#....#..\n..#####...",
         "E":"..######..\n..#.......\n..#####...\n..#.......\n..######..",
         "K":"..#...#...\n..#..#....\n..##......\n..#..#....\n..#...#..." }
name = "GEEK"
for ch in name:
    print(font.get(ch, "Character not available"))

Output:

..######..

..#.......

..#.####..

..#....#..

..#####...

..######..

..#.......

..#####...

..#.......

..######..

..######..

..#.......

..#####...

..#.......

..######..

..#...#...

..#..#....

..##......

..#..#....

..#...#...

Explanation:

• font= {...} maps each letter to a single multi-line string (the whole block).
• name = "GEEK" input word.
• for ch in name: iterate over each letter.
• print(art.get(ch, "Character not available")) fetch and print the block; fallback if missing.

Using User-Defined Function

This method defines a function that prints the pattern for each character by using if / elif checks.

def show(c):
    c = c.upper()
    if c == "G":
        print("..######..\n..#.......\n..#.####..\n..#....#..\n..#####...")
    elif c == "E":
        print("..######..\n..#.......\n..#####...\n..#.......\n..######..")
    elif c == "K":
        print("..#...#...\n..#..#....\n..##......\n..#..#....\n..#...#...")

name = "GEEK"
for ch in name:
    show(ch)
    print()

Output:

..######..

..#.......

..#.####..

..#....#..

..#####...

..######..

..#.......

..#####...

..#.......

..######..

..######..

..#.......

..#####...

..#.......

..######..

..#...#...

..#..#....

..##......

..#..#....

..#...#...

Explanation:

• def show(c): defines show, which prints the ASCII block for c.
• c = c.upper() normalize to uppercase.
• if c == "G": ... elif c == "E": ... choose the right block and print() it.
• for ch in name: loop letters in the word.
• show(ch) print letter's block.

Using Multiple If-Else Blocks

This traditional method manually checks each character and prints its pattern. It is clear but repetitive.

name = "GEEK"
for ch in name:
    if ch == "G":
        print("..######..\n..#.......\n..#.####..\n..#....#..\n..#####...")
    elif ch == "E":
        print("..######..\n..#.......\n..#####...\n..#.......\n..######..")
    elif ch == "K":
        print("..#...#...\n..#..#....\n..##......\n..#..#....\n..#...#...")
    print()

Output:

..######..

..#.......

..#.####..

..#....#..

..#####...

..######..

..#.......

..#####...

..#.......

..######..

..######..

..#.......

..#####...

..#.......

..######..

..#...#...

..#..#....

..##......

..#..#....

..#...#...

Explanation:

• name = "GEEK" input word.
• for ch in name: iterate letters.
• if ch == "G": print(...) directly print the block for each matched case.