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            "questionId": "1273",
            "questionFrontendId": "1170",
            "categoryTitle": "Algorithms",
            "boundTopicId": 22197,
            "title": "Compare Strings by Frequency of the Smallest Character",
            "titleSlug": "compare-strings-by-frequency-of-the-smallest-character",
            "content": "<p>Let the function <code>f(s)</code> be the <strong>frequency of the lexicographically smallest character</strong> in a non-empty string <code>s</code>. For example, if <code>s = &quot;dcce&quot;</code> then <code>f(s) = 2</code> because the lexicographically smallest character is <code>&#39;c&#39;</code>, which has a frequency of 2.</p>\n\n<p>You are given an array of strings <code>words</code> and another array of query strings <code>queries</code>. For each query <code>queries[i]</code>, count the <strong>number of words</strong> in <code>words</code> such that <code>f(queries[i])</code> &lt; <code>f(W)</code> for each <code>W</code> in <code>words</code>.</p>\n\n<p>Return <em>an integer array </em><code>answer</code><em>, where each </em><code>answer[i]</code><em> is the answer to the </em><code>i<sup>th</sup></code><em> query</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [&quot;cbd&quot;], words = [&quot;zaaaz&quot;]\n<strong>Output:</strong> [1]\n<strong>Explanation:</strong> On the first query we have f(&quot;cbd&quot;) = 1, f(&quot;zaaaz&quot;) = 3 so f(&quot;cbd&quot;) &lt; f(&quot;zaaaz&quot;).\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [&quot;bbb&quot;,&quot;cc&quot;], words = [&quot;a&quot;,&quot;aa&quot;,&quot;aaa&quot;,&quot;aaaa&quot;]\n<strong>Output:</strong> [1,2]\n<strong>Explanation:</strong> On the first query only f(&quot;bbb&quot;) &lt; f(&quot;aaaa&quot;). On the second query both f(&quot;aaa&quot;) and f(&quot;aaaa&quot;) are both &gt; f(&quot;cc&quot;).\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= queries.length &lt;= 2000</code></li>\n\t<li><code>1 &lt;= words.length &lt;= 2000</code></li>\n\t<li><code>1 &lt;= queries[i].length, words[i].length &lt;= 10</code></li>\n\t<li><code>queries[i][j]</code>, <code>words[i][j]</code> consist of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "比较字符串最小字母出现频次",
            "translatedContent": "<p>定义一个函数 <code>f(s)</code>，统计 <code>s</code>  中<strong>（按字典序比较）最小字母的出现频次</strong> ，其中 <code>s</code> 是一个非空字符串。</p>\n\n<p>例如，若 <code>s = \"dcce\"</code>，那么 <code>f(s) = 2</code>，因为字典序最小字母是 <code>\"c\"</code>，它出现了 2 次。</p>\n\n<p>现在，给你两个字符串数组待查表 <code>queries</code> 和词汇表 <code>words</code> 。对于每次查询 <code>queries[i]</code> ，需统计 <code>words</code> 中满足 <code>f(queries[i])</code> < <code>f(W)</code> 的<strong> 词的数目</strong> ，<code>W</code> 表示词汇表 <code>words</code> 中的每个词。</p>\n\n<p>请你返回一个整数数组 <code>answer</code> 作为答案，其中每个 <code>answer[i]</code> 是第 <code>i</code> 次查询的结果。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>queries = [\"cbd\"], words = [\"zaaaz\"]\n<strong>输出：</strong>[1]\n<strong>解释：</strong>查询 f(\"cbd\") = 1，而 f(\"zaaaz\") = 3 所以 f(\"cbd\") < f(\"zaaaz\")。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>queries = [\"bbb\",\"cc\"], words = [\"a\",\"aa\",\"aaa\",\"aaaa\"]\n<strong>输出：</strong>[1,2]\n<strong>解释：</strong>第一个查询 f(\"bbb\") < f(\"aaaa\")，第二个查询 f(\"aaa\") 和 f(\"aaaa\") 都 > f(\"cc\")。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= queries.length <= 2000</code></li>\n\t<li><code>1 <= words.length <= 2000</code></li>\n\t<li><code>1 <= queries[i].length, words[i].length <= 10</code></li>\n\t<li><code>queries[i][j]</code>、<code>words[i][j]</code> 都由小写英文字母组成</li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def numSmallerByFrequency(self, queries, words):\n        \"\"\"\n        :type queries: List[str]\n        :type words: List[str]\n        :rtype: List[int]\n        \"\"\"",
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                "For each string from words calculate the leading count and store it in an array, then sort the integer array.",
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