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小墨 authored 2022-03-29 12:55 +08:00 . update
<p>You are given a <strong>0-indexed</strong> binary string <code>s</code> and two integers <code>minJump</code> and <code>maxJump</code>. In the beginning, you are standing at index <code>0</code>, which is equal to <code>&#39;0&#39;</code>. You can move from index <code>i</code> to index <code>j</code> if the following conditions are fulfilled:</p>
<ul>
<li><code>i + minJump &lt;= j &lt;= min(i + maxJump, s.length - 1)</code>, and</li>
<li><code>s[j] == &#39;0&#39;</code>.</li>
</ul>
<p>Return <code>true</code><i> if you can reach index </i><code>s.length - 1</code><i> in </i><code>s</code><em>, or </em><code>false</code><em> otherwise.</em></p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<pre>
<strong>Input:</strong> s = &quot;<u>0</u>11<u>0</u>1<u>0</u>&quot;, minJump = 2, maxJump = 3
<strong>Output:</strong> true
<strong>Explanation:</strong>
In the first step, move from index 0 to index 3.
In the second step, move from index 3 to index 5.
</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> s = &quot;01101110&quot;, minJump = 2, maxJump = 3
<strong>Output:</strong> false
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>2 &lt;= s.length &lt;= 10<sup>5</sup></code></li>
<li><code>s[i]</code> is either <code>&#39;0&#39;</code> or <code>&#39;1&#39;</code>.</li>
<li><code>s[0] == &#39;0&#39;</code></li>
<li><code>1 &lt;= minJump &lt;= maxJump &lt; s.length</code></li>
</ul>
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力扣题库(完整版)
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