代码拉取完成,页面将自动刷新
同步操作将从 小墨/力扣题库(完整版) 强制同步,此操作会覆盖自 Fork 仓库以来所做的任何修改,且无法恢复!!!
确定后同步将在后台操作,完成时将刷新页面,请耐心等待。
<p>You are given two integers <code>n</code> and <code>k</code> and two integer arrays <code>speed</code> and <code>efficiency</code> both of length <code>n</code>. There are <code>n</code> engineers numbered from <code>1</code> to <code>n</code>. <code>speed[i]</code> and <code>efficiency[i]</code> represent the speed and efficiency of the <code>i<sup>th</sup></code> engineer respectively.</p>
<p>Choose <strong>at most</strong> <code>k</code> different engineers out of the <code>n</code> engineers to form a team with the maximum <strong>performance</strong>.</p>
<p>The performance of a team is the sum of their engineers' speeds multiplied by the minimum efficiency among their engineers.</p>
<p>Return <em>the maximum performance of this team</em>. Since the answer can be a huge number, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>
<p> </p>
<p><strong>Example 1:</strong></p>
<pre>
<strong>Input:</strong> n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 2
<strong>Output:</strong> 60
<strong>Explanation:</strong>
We have the maximum performance of the team by selecting engineer 2 (with speed=10 and efficiency=4) and engineer 5 (with speed=5 and efficiency=7). That is, performance = (10 + 5) * min(4, 7) = 60.
</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 3
<strong>Output:</strong> 68
<strong>Explanation:
</strong>This is the same example as the first but k = 3. We can select engineer 1, engineer 2 and engineer 5 to get the maximum performance of the team. That is, performance = (2 + 10 + 5) * min(5, 4, 7) = 68.
</pre>
<p><strong>Example 3:</strong></p>
<pre>
<strong>Input:</strong> n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 4
<strong>Output:</strong> 72
</pre>
<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= k <= n <= 10<sup>5</sup></code></li>
<li><code>speed.length == n</code></li>
<li><code>efficiency.length == n</code></li>
<li><code>1 <= speed[i] <= 10<sup>5</sup></code></li>
<li><code>1 <= efficiency[i] <= 10<sup>8</sup></code></li>
</ul>
此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。
如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。