1 Star 41 Fork 18

小墨/力扣题库(完整版)

加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
文件
克隆/下载
binary-search.html 1.13 KB
一键复制 编辑 原始数据 按行查看 历史
小墨 提交于 2023-12-09 18:42 +08:00 . 存量题库数据更新
<p>Given an array of integers <code>nums</code> which is sorted in ascending order, and an integer <code>target</code>, write a function to search <code>target</code> in <code>nums</code>. If <code>target</code> exists, then return its index. Otherwise, return <code>-1</code>.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [-1,0,3,5,9,12], target = 9
<strong>Output:</strong> 4
<strong>Explanation:</strong> 9 exists in nums and its index is 4
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [-1,0,3,5,9,12], target = 2
<strong>Output:</strong> -1
<strong>Explanation:</strong> 2 does not exist in nums so return -1
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>
<li><code>-10<sup>4</sup> &lt; nums[i], target &lt; 10<sup>4</sup></code></li>
<li>All the integers in <code>nums</code> are <strong>unique</strong>.</li>
<li><code>nums</code> is sorted in ascending order.</li>
</ul>
Loading...
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
1
https://gitee.com/coder-xiaomo/leetcode-problemset.git
git@gitee.com:coder-xiaomo/leetcode-problemset.git
coder-xiaomo
leetcode-problemset
力扣题库(完整版)
master

搜索帮助