1 Star 41 Fork 18

小墨/力扣题库(完整版)

加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
文件
克隆/下载
contains-duplicate-iii.html 1.46 KB
一键复制 编辑 原始数据 按行查看 历史
小墨 提交于 2023-12-09 18:42 +08:00 . 存量题库数据更新
<p>You are given an integer array <code>nums</code> and two integers <code>indexDiff</code> and <code>valueDiff</code>.</p>
<p>Find a pair of indices <code>(i, j)</code> such that:</p>
<ul>
<li><code>i != j</code>,</li>
<li><code>abs(i - j) &lt;= indexDiff</code>.</li>
<li><code>abs(nums[i] - nums[j]) &lt;= valueDiff</code>, and</li>
</ul>
<p>Return <code>true</code><em> if such pair exists or </em><code>false</code><em> otherwise</em>.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [1,2,3,1], indexDiff = 3, valueDiff = 0
<strong>Output:</strong> true
<strong>Explanation:</strong> We can choose (i, j) = (0, 3).
We satisfy the three conditions:
i != j --&gt; 0 != 3
abs(i - j) &lt;= indexDiff --&gt; abs(0 - 3) &lt;= 3
abs(nums[i] - nums[j]) &lt;= valueDiff --&gt; abs(1 - 1) &lt;= 0
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [1,5,9,1,5,9], indexDiff = 2, valueDiff = 3
<strong>Output:</strong> false
<strong>Explanation:</strong> After trying all the possible pairs (i, j), we cannot satisfy the three conditions, so we return false.
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>2 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
<li><code>1 &lt;= indexDiff &lt;= nums.length</code></li>
<li><code>0 &lt;= valueDiff &lt;= 10<sup>9</sup></code></li>
</ul>
Loading...
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
1
https://gitee.com/coder-xiaomo/leetcode-problemset.git
git@gitee.com:coder-xiaomo/leetcode-problemset.git
coder-xiaomo
leetcode-problemset
力扣题库(完整版)
master

搜索帮助