代码拉取完成,页面将自动刷新
<p>You are given an array of <code>intervals</code>, where <code>intervals[i] = [start<sub>i</sub>, end<sub>i</sub>]</code> and each <code>start<sub>i</sub></code> is <strong>unique</strong>.</p>
<p>The <strong>right interval</strong> for an interval <code>i</code> is an interval <code>j</code> such that <code>start<sub>j</sub> >= end<sub>i</sub></code> and <code>start<sub>j</sub></code> is <strong>minimized</strong>. Note that <code>i</code> may equal <code>j</code>.</p>
<p>Return <em>an array of <strong>right interval</strong> indices for each interval <code>i</code></em>. If no <strong>right interval</strong> exists for interval <code>i</code>, then put <code>-1</code> at index <code>i</code>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> intervals = [[1,2]]
<strong>Output:</strong> [-1]
<strong>Explanation:</strong> There is only one interval in the collection, so it outputs -1.
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> intervals = [[3,4],[2,3],[1,2]]
<strong>Output:</strong> [-1,0,1]
<strong>Explanation:</strong> There is no right interval for [3,4].
The right interval for [2,3] is [3,4] since start<sub>0</sub> = 3 is the smallest start that is >= end<sub>1</sub> = 3.
The right interval for [1,2] is [2,3] since start<sub>1</sub> = 2 is the smallest start that is >= end<sub>2</sub> = 2.
</pre>
<p><strong class="example">Example 3:</strong></p>
<pre>
<strong>Input:</strong> intervals = [[1,4],[2,3],[3,4]]
<strong>Output:</strong> [-1,2,-1]
<strong>Explanation:</strong> There is no right interval for [1,4] and [3,4].
The right interval for [2,3] is [3,4] since start<sub>2</sub> = 3 is the smallest start that is >= end<sub>1</sub> = 3.
</pre>
<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= intervals.length <= 2 * 10<sup>4</sup></code></li>
<li><code>intervals[i].length == 2</code></li>
<li><code>-10<sup>6</sup> <= start<sub>i</sub> <= end<sub>i</sub> <= 10<sup>6</sup></code></li>
<li>The start point of each interval is <strong>unique</strong>.</li>
</ul>
此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。
如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。