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"title": "Apply Bitwise Operations to Make Strings Equal",
"titleSlug": "apply-bitwise-operations-to-make-strings-equal",
"content": "<p>You are given two <strong>0-indexed binary</strong> strings <code>s</code> and <code>target</code> of the same length <code>n</code>. You can do the following operation on <code>s</code> <strong>any</strong> number of times:</p>\n\n<ul>\n\t<li>Choose two <strong>different</strong> indices <code>i</code> and <code>j</code> where <code>0 <= i, j < n</code>.</li>\n\t<li>Simultaneously, replace <code>s[i]</code> with (<code>s[i]</code> <strong>OR</strong> <code>s[j]</code>) and <code>s[j]</code> with (<code>s[i]</code> <strong>XOR</strong> <code>s[j]</code>).</li>\n</ul>\n\n<p>For example, if <code>s = "0110"</code>, you can choose <code>i = 0</code> and <code>j = 2</code>, then simultaneously replace <code>s[0]</code> with (<code>s[0]</code> <strong>OR</strong> <code>s[2]</code> = <code>0</code> <strong>OR</strong> <code>1</code> = <code>1</code>), and <code>s[2]</code> with (<code>s[0]</code> <strong>XOR</strong> <code>s[2]</code> = <code>0</code> <strong>XOR</strong> <code>1</code> = <code>1</code>), so we will have <code>s = "1110"</code>.</p>\n\n<p>Return <code>true</code> <em>if you can make the string </em><code>s</code><em> equal to </em><code>target</code><em>, or </em><code>false</code><em> otherwise</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "1010", target = "0110"\n<strong>Output:</strong> true\n<strong>Explanation:</strong> We can do the following operations:\n- Choose i = 2 and j = 0. We have now s = "<strong><u>0</u></strong>0<strong><u>1</u></strong>0".\n- Choose i = 2 and j = 1. We have now s = "0<strong><u>11</u></strong>0".\nSince we can make s equal to target, we return true.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "11", target = "00"\n<strong>Output:</strong> false\n<strong>Explanation:</strong> It is not possible to make s equal to target with any number of operations.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == s.length == target.length</code></li>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> and <code>target</code> consist of only the digits <code>0</code> and <code>1</code>.</li>\n</ul>\n",
"translatedTitle": "执行逐位运算使字符串相等",
"translatedContent": "<p>给你两个下标从 <strong>0</strong> 开始的 <strong>二元</strong> 字符串 <code>s</code> 和 <code>target</code> ，两个字符串的长度均为 <code>n</code> 。你可以对 <code>s</code> 执行下述操作 <strong>任意</strong> 次：</p>\n\n<ul>\n\t<li>选择两个 <strong>不同</strong> 的下标 <code>i</code> 和 <code>j</code> ，其中 <code>0 <= i, j < n</code> 。</li>\n\t<li>同时，将 <code>s[i]</code> 替换为 (<code>s[i]</code> <strong>OR</strong> <code>s[j]</code>) ，<code>s[j]</code> 替换为 (<code>s[i]</code> <strong>XOR</strong> <code>s[j]</code>) 。</li>\n</ul>\n\n<p>例如，如果 <code>s = \"0110\"</code> ，你可以选择 <code>i = 0</code> 和 <code>j = 2</code>，然后同时将 <code>s[0]</code> 替换为 (<code>s[0]</code> <strong>OR</strong> <code>s[2]</code> = <code>0</code> <strong>OR</strong> <code>1</code> = <code>1</code>)，并将 <code>s[2]</code> 替换为 (<code>s[0]</code> <strong>XOR</strong> <code>s[2]</code> = <code>0</code> <strong>XOR</strong> <code>1</code> = <code>1</code>)，最终得到 <code>s = \"1110\"</code> 。</p>\n\n<p>如果可以使 <code>s</code> 等于 <code>target</code> ，返回 <code>true</code> ，否则，返回 <code>false</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>s = \"1010\", target = \"0110\"\n<strong>输出：</strong>true\n<strong>解释：</strong>可以执行下述操作：\n- 选择 i = 2 和 j = 0 ，得到 s = \"<em><strong>0</strong></em>0<em><strong>1</strong></em>0\".\n- 选择 i = 2 和 j = 1 ，得到 s = \"0<em><strong>11</strong></em>0\".\n可以使 s 等于 target ，返回 true 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>s = \"11\", target = \"00\"\n<strong>输出：</strong>false\n<strong>解释：</strong>执行任意次操作都无法使 s 等于 target 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == s.length == target.length</code></li>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 和 <code>target</code> 仅由数字 <code>0</code> 和 <code>1</code> 组成</li>\n</ul>\n",
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