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"categoryTitle": "Algorithms",
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"title": "Check If a String Can Break Another String",
"titleSlug": "check-if-a-string-can-break-another-string",
"content": "<p>Given two strings: <code>s1</code> and <code>s2</code> with the same size, check if some permutation of string <code>s1</code> can break some permutation of string <code>s2</code> or vice-versa. In other words <code>s2</code> can break <code>s1</code> or vice-versa.</p>\n\n<p>A string <code>x</code> can break string <code>y</code> (both of size <code>n</code>) if <code>x[i] >= y[i]</code> (in alphabetical order) for all <code>i</code> between <code>0</code> and <code>n-1</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = "abc", s2 = "xya"\n<strong>Output:</strong> true\n<strong>Explanation:</strong> "ayx" is a permutation of s2="xya" which can break to string "abc" which is a permutation of s1="abc".\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = "abe", s2 = "acd"\n<strong>Output:</strong> false \n<strong>Explanation:</strong> All permutations for s1="abe" are: "abe", "aeb", "bae", "bea", "eab" and "eba" and all permutation for s2="acd" are: "acd", "adc", "cad", "cda", "dac" and "dca". However, there is not any permutation from s1 which can break some permutation from s2 and vice-versa.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = "leetcodee", s2 = "interview"\n<strong>Output:</strong> true\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>s1.length == n</code></li>\n\t<li><code>s2.length == n</code></li>\n\t<li><code>1 <= n <= 10^5</code></li>\n\t<li>All strings consist of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "检查一个字符串是否可以打破另一个字符串",
"translatedContent": "<p>给你两个字符串 <code>s1</code> 和 <code>s2</code> ,它们长度相等,请你检查是否存在一个 <code>s1</code> 的排列可以打破 <code>s2</code> 的一个排列,或者是否存在一个 <code>s2</code> 的排列可以打破 <code>s1</code> 的一个排列。</p>\n\n<p>字符串 <code>x</code> 可以打破字符串 <code>y</code> (两者长度都为 <code>n</code> )需满足对于所有 <code>i</code>(在 <code>0</code> 到 <code>n - 1</code> 之间)都有 <code>x[i] >= y[i]</code>(字典序意义下的顺序)。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong>s1 = "abc", s2 = "xya"\n<strong>输出:</strong>true\n<strong>解释:</strong>"ayx" 是 s2="xya" 的一个排列,"abc" 是字符串 s1="abc" 的一个排列,且 "ayx" 可以打破 "abc" 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong>s1 = "abe", s2 = "acd"\n<strong>输出:</strong>false \n<strong>解释:</strong>s1="abe" 的所有排列包括:"abe","aeb","bae","bea","eab" 和 "eba" ,s2="acd" 的所有排列包括:"acd","adc","cad","cda","dac" 和 "dca"。然而没有任何 s1 的排列可以打破 s2 的排列。也没有 s2 的排列能打破 s1 的排列。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre><strong>输入:</strong>s1 = "leetcodee", s2 = "interview"\n<strong>输出:</strong>true\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>s1.length == n</code></li>\n\t<li><code>s2.length == n</code></li>\n\t<li><code>1 <= n <= 10^5</code></li>\n\t<li>所有字符串都只包含小写英文字母。</li>\n</ul>\n",
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