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"questionFrontendId": "1585",
"categoryTitle": "Algorithms",
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"title": "Check If String Is Transformable With Substring Sort Operations",
"titleSlug": "check-if-string-is-transformable-with-substring-sort-operations",
"content": "<p>Given two strings <code>s</code> and <code>t</code>, transform string <code>s</code> into string <code>t</code> using the following operation any number of times:</p>\n\n<ul>\n\t<li>Choose a <strong>non-empty</strong> substring in <code>s</code> and sort it in place so the characters are in <strong>ascending order</strong>.\n\n\t<ul>\n\t\t<li>For example, applying the operation on the underlined substring in <code>"1<u>4234</u>"</code> results in <code>"1<u>2344</u>"</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>Return <code>true</code> if <em>it is possible to transform <code>s</code> into <code>t</code></em>. Otherwise, return <code>false</code>.</p>\n\n<p>A <strong>substring</strong> is a contiguous sequence of characters within a string.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "84532", t = "34852"\n<strong>Output:</strong> true\n<strong>Explanation:</strong> You can transform s into t using the following sort operations:\n"84<u>53</u>2" (from index 2 to 3) -> "84<u>35</u>2"\n"<u>843</u>52" (from index 0 to 2) -> "<u>348</u>52"\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "34521", t = "23415"\n<strong>Output:</strong> true\n<strong>Explanation:</strong> You can transform s into t using the following sort operations:\n"<u>3452</u>1" -> "<u>2345</u>1"\n"234<u>51</u>" -> "234<u>15</u>"\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "12345", t = "12435"\n<strong>Output:</strong> false\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>s.length == t.length</code></li>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> and <code>t</code> consist of only digits.</li>\n</ul>\n",
"translatedTitle": "检查字符串是否可以通过排序子字符串得到另一个字符串",
"translatedContent": "<p>给你两个字符串 <code>s</code> 和 <code>t</code> ,请你通过若干次以下操作将字符串 <code>s</code> 转化成字符串 <code>t</code> :</p>\n\n<ul>\n\t<li>选择 <code>s</code> 中一个 <strong>非空</strong> 子字符串并将它包含的字符就地 <strong>升序</strong> 排序。</li>\n</ul>\n\n<p>比方说,对下划线所示的子字符串进行操作可以由 <code>"1<strong>4234</strong>"</code> 得到 <code>"1<strong>2344</strong>"</code> 。</p>\n\n<p>如果可以将字符串 <code>s</code> 变成 <code>t</code> ,返回 <code>true</code> 。否则,返回 <code>false</code> 。</p>\n\n<p>一个 <strong>子字符串</strong> 定义为一个字符串中连续的若干字符。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>s = "84532", t = "34852"\n<strong>输出:</strong>true\n<strong>解释:</strong>你可以按以下操作将 s 转变为 t :\n"84<strong>53</strong>2" (从下标 2 到下标 3)-> "84<strong>35</strong>2"\n"<strong>843</strong>52" (从下标 0 到下标 2) -> "<strong>348</strong>52"\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>s = "34521", t = "23415"\n<strong>输出:</strong>true\n<strong>解释:</strong>你可以按以下操作将 s 转变为 t :\n"<strong>3452</strong>1" -> "<strong>2345</strong>1"\n"234<strong>51</strong>" -> "234<strong>15</strong>"\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong>s = "12345", t = "12435"\n<strong>输出:</strong>false\n</pre>\n\n<p><strong>示例 4:</strong></p>\n\n<pre>\n<strong>输入:</strong>s = "1", t = "2"\n<strong>输出:</strong>false\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>s.length == t.length</code></li>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 和 <code>t</code> 都只包含数字字符,即 <code>'0'</code> 到 <code>'9'</code> 。</li>\n</ul>\n",
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"hints": [
"Suppose the first digit you need is 'd'. How can you determine if it's possible to get that digit there?",
"Consider swapping adjacent characters to maintain relative ordering."
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