代码拉取完成,页面将自动刷新
同步操作将从 小墨/力扣题库(完整版) 强制同步,此操作会覆盖自 Fork 仓库以来所做的任何修改,且无法恢复!!!
确定后同步将在后台操作,完成时将刷新页面,请耐心等待。
<p>You are given a nested list of integers <code>nestedList</code>. Each element is either an integer or a list whose elements may also be integers or other lists. Implement an iterator to flatten it.</p>
<p>Implement the <code>NestedIterator</code> class:</p>
<ul>
<li><code>NestedIterator(List<NestedInteger> nestedList)</code> Initializes the iterator with the nested list <code>nestedList</code>.</li>
<li><code>int next()</code> Returns the next integer in the nested list.</li>
<li><code>boolean hasNext()</code> Returns <code>true</code> if there are still some integers in the nested list and <code>false</code> otherwise.</li>
</ul>
<p>Your code will be tested with the following pseudocode:</p>
<pre>
initialize iterator with nestedList
res = []
while iterator.hasNext()
append iterator.next() to the end of res
return res
</pre>
<p>If <code>res</code> matches the expected flattened list, then your code will be judged as correct.</p>
<p> </p>
<p><strong>Example 1:</strong></p>
<pre>
<strong>Input:</strong> nestedList = [[1,1],2,[1,1]]
<strong>Output:</strong> [1,1,2,1,1]
<strong>Explanation:</strong> By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,1,2,1,1].
</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> nestedList = [1,[4,[6]]]
<strong>Output:</strong> [1,4,6]
<strong>Explanation:</strong> By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,4,6].
</pre>
<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= nestedList.length <= 500</code></li>
<li>The values of the integers in the nested list is in the range <code>[-10<sup>6</sup>, 10<sup>6</sup>]</code>.</li>
</ul>
此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。
如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。