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Gui/力扣题库(完整版)

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小墨 提交于 2022-03-29 12:55 +08:00 . update
<p>Given an array of non-negative integers <code>arr</code>, you are initially positioned at <code>start</code>&nbsp;index of the array. When you are at index <code>i</code>, you can jump&nbsp;to <code>i + arr[i]</code> or <code>i - arr[i]</code>, check if you can reach to <strong>any</strong> index with value 0.</p>
<p>Notice that you can not jump outside of the array at any time.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<pre>
<strong>Input:</strong> arr = [4,2,3,0,3,1,2], start = 5
<strong>Output:</strong> true
<strong>Explanation:</strong>
All possible ways to reach at index 3 with value 0 are:
index 5 -&gt; index 4 -&gt; index 1 -&gt; index 3
index 5 -&gt; index 6 -&gt; index 4 -&gt; index 1 -&gt; index 3
</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> arr = [4,2,3,0,3,1,2], start = 0
<strong>Output:</strong> true
<strong>Explanation:
</strong>One possible way to reach at index 3 with value 0 is:
index 0 -&gt; index 4 -&gt; index 1 -&gt; index 3
</pre>
<p><strong>Example 3:</strong></p>
<pre>
<strong>Input:</strong> arr = [3,0,2,1,2], start = 2
<strong>Output:</strong> false
<strong>Explanation: </strong>There is no way to reach at index 1 with value 0.
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= arr.length &lt;= 5 * 10<sup>4</sup></code></li>
<li><code>0 &lt;= arr[i] &lt;&nbsp;arr.length</code></li>
<li><code>0 &lt;= start &lt; arr.length</code></li>
</ul>
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力扣题库(完整版)
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