代码拉取完成,页面将自动刷新
同步操作将从 小墨/力扣题库(完整版) 强制同步,此操作会覆盖自 Fork 仓库以来所做的任何修改,且无法恢复!!!
确定后同步将在后台操作,完成时将刷新页面,请耐心等待。
<p>You are given a 0-indexed integer array <code>nums</code>. You are allowed to permute <code>nums</code> into a new array <code>perm</code> of your choosing.</p>
<p>We define the <strong>greatness</strong> of <code>nums</code> be the number of indices <code>0 <= i < nums.length</code> for which <code>perm[i] > nums[i]</code>.</p>
<p>Return <em>the <strong>maximum</strong> possible greatness you can achieve after permuting</em> <code>nums</code>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [1,3,5,2,1,3,1]
<strong>Output:</strong> 4
<strong>Explanation:</strong> One of the optimal rearrangements is perm = [2,5,1,3,3,1,1].
At indices = 0, 1, 3, and 4, perm[i] > nums[i]. Hence, we return 4.</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [1,2,3,4]
<strong>Output:</strong> 3
<strong>Explanation:</strong> We can prove the optimal perm is [2,3,4,1].
At indices = 0, 1, and 2, perm[i] > nums[i]. Hence, we return 3.
</pre>
<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
<li><code>0 <= nums[i] <= 10<sup>9</sup></code></li>
</ul>
此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。
如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。