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小墨 authored 2023-12-09 18:42 +08:00 . 存量题库数据更新
<p>Table: <code>Employees</code></p>
<pre>
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| employee_id | int |
| name | varchar |
| salary | int |
+-------------+---------+
employee_id is the primary key (column with unique values) for this table.
Each row of this table indicates the employee ID, employee name, and salary.
</pre>
<p>&nbsp;</p>
<p>Write a solution to calculate the bonus of each employee. The bonus of an employee is <code>100%</code> of their salary if the ID of the employee is <strong>an odd number</strong> and <strong>the employee&#39;s name does not start with the character </strong><code>&#39;M&#39;</code>. The bonus of an employee is <code>0</code> otherwise.</p>
<p>Return the result table ordered by <code>employee_id</code>.</p>
<p>The&nbsp;result format is in the following example.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong>
Employees table:
+-------------+---------+--------+
| employee_id | name | salary |
+-------------+---------+--------+
| 2 | Meir | 3000 |
| 3 | Michael | 3800 |
| 7 | Addilyn | 7400 |
| 8 | Juan | 6100 |
| 9 | Kannon | 7700 |
+-------------+---------+--------+
<strong>Output:</strong>
+-------------+-------+
| employee_id | bonus |
+-------------+-------+
| 2 | 0 |
| 3 | 0 |
| 7 | 7400 |
| 8 | 0 |
| 9 | 7700 |
+-------------+-------+
<strong>Explanation:</strong>
The employees with IDs 2 and 8 get 0 bonus because they have an even employee_id.
The employee with ID 3 gets 0 bonus because their name starts with &#39;M&#39;.
The rest of the employees get a 100% bonus.
</pre>
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