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| 1 | +/* |
| 2 | +1027. Longest Arithmetic Subsequence |
| 3 | +
|
| 4 | +Given an array nums of integers, return the length of the longest arithmetic subsequence in nums. |
| 5 | +Note that: |
| 6 | +A subsequence is an array that can be derived from another array by deleting some or no elements without changing the order of the remaining elements. |
| 7 | +A sequence seq is arithmetic if seq[i + 1] - seq[i] are all the same value (for 0 <= i < seq.length - 1). |
| 8 | +
|
| 9 | +Example 1: |
| 10 | +Input: nums = [3,6,9,12] |
| 11 | +Output: 4 |
| 12 | +Explanation: The whole array is an arithmetic sequence with steps of length = 3. |
| 13 | +
|
| 14 | +Example 2: |
| 15 | +Input: nums = [9,4,7,2,10] |
| 16 | +Output: 3 |
| 17 | +Explanation: The longest arithmetic subsequence is [4,7,10]. |
| 18 | +
|
| 19 | +Example 3: |
| 20 | +Input: nums = [20,1,15,3,10,5,8] |
| 21 | +Output: 4 |
| 22 | +Explanation: The longest arithmetic subsequence is [20,15,10,5]. |
| 23 | + |
| 24 | +
|
| 25 | +Constraints: |
| 26 | +
|
| 27 | +2 <= nums.length <= 1000 |
| 28 | +0 <= nums[i] <= 500 |
| 29 | +*/ |
| 30 | +class Solution { |
| 31 | + static HashMap<String,Integer> map; |
| 32 | + public int longestArithSeqLength(int[] nums) { |
| 33 | + // Recursion::1. |
| 34 | + //return solveRec(nums,0,501,-1,0); |
| 35 | + |
| 36 | + // Recursion Modiied::2 |
| 37 | + // return solve(Integer.MIN_VALUE,Integer.MIN_VALUE,nums,0); |
| 38 | + |
| 39 | + // map =new HashMap<>(); |
| 40 | + // return solveMemo(Integer.MIN_VALUE,Integer.MIN_VALUE,nums,0); |
| 41 | + return solveTab(nums); |
| 42 | + |
| 43 | + } |
| 44 | + public static int solveRec(int[] nums,int indx,int diff,int prev,int len){ |
| 45 | + //base case::: |
| 46 | + if(indx>=nums.length) return 0; |
| 47 | + if(diff==501){ |
| 48 | + int pick=0; |
| 49 | + if(len<1){ |
| 50 | + pick =1+solveRec(nums,indx+1,diff,indx,len+1); |
| 51 | + }else { |
| 52 | + pick =1+solveRec(nums,indx+1,nums[indx]-nums[prev],indx,len+1); |
| 53 | + } |
| 54 | + int notpick =solveRec(nums,indx+1,diff,prev,len); |
| 55 | + return Math.max(pick,notpick); |
| 56 | + }else{ |
| 57 | + int pick=0; |
| 58 | + if(nums[indx]-nums[prev]==diff){ |
| 59 | + pick =1+solveRec(nums,indx+1,diff,indx,len+1); |
| 60 | + } |
| 61 | + int notpick =solveRec(nums,indx+1,diff,prev,len); |
| 62 | + return Math.max(pick,notpick); |
| 63 | + } |
| 64 | + } |
| 65 | + public static int solve(int prev,int diff,int[] nums,int indx){ |
| 66 | + if(indx==nums.length) return 0; |
| 67 | + int pick=0; |
| 68 | + int notpick=0; |
| 69 | + |
| 70 | + if(prev==Integer.MIN_VALUE){ |
| 71 | + pick =1+solve(nums[indx],diff,nums,indx+1); |
| 72 | + }else if(diff==Integer.MIN_VALUE || diff == nums[indx]-prev){ |
| 73 | + pick=1+solve(nums[indx],nums[indx]-prev,nums,indx+1); |
| 74 | + } |
| 75 | + notpick =solve(prev,diff,nums,indx+1); |
| 76 | + return Math.max(pick,notpick); |
| 77 | + } |
| 78 | + public static int solveMemo(int prev,int diff,int[] nums,int indx){ |
| 79 | + if(indx==nums.length) return 0; |
| 80 | + |
| 81 | + String key =indx+"-"+prev+"-"+diff; |
| 82 | + if(map.containsKey(key)){ |
| 83 | + return map.get(key); |
| 84 | + } |
| 85 | + int pick=0; |
| 86 | + int notpick=0; |
| 87 | + |
| 88 | + if(prev==Integer.MIN_VALUE){ |
| 89 | + pick =1+solveMemo(nums[indx],diff,nums,indx+1); |
| 90 | + }else if(diff==Integer.MIN_VALUE || diff == nums[indx]-prev){ |
| 91 | + pick=1+solveMemo(nums[indx],nums[indx]-prev,nums,indx+1); |
| 92 | + } |
| 93 | + notpick =solveMemo(prev,diff,nums,indx+1); |
| 94 | + map.put(key,Math.max(pick,notpick)); |
| 95 | + return Math.max(pick,notpick); |
| 96 | + } |
| 97 | + public static int solveTab(int[] nums){ |
| 98 | + int n=nums.length; |
| 99 | + |
| 100 | + if(n<=2) return n; |
| 101 | + Map<Integer, Integer>[] dp = new HashMap[n]; |
| 102 | + int longest=2; |
| 103 | + for(int i=0;i<n;i++){ |
| 104 | + dp[i] =new HashMap<>(); |
| 105 | + for(int j=0;j<i;j++){ |
| 106 | + int diff =nums[i]-nums[j]; |
| 107 | + dp[i].put(diff,dp[j].getOrDefault(diff,1)+1); |
| 108 | + longest =Math.max(longest,dp[i].get(diff)); |
| 109 | + } |
| 110 | + } |
| 111 | + return longest; |
| 112 | + } |
| 113 | + |
| 114 | +} |
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