public class Solution extends Object
832 - Flipping an Image.
Easy
Given an n x n binary matrix image, flip the image horizontally , then invert it, and return the resulting image.
To flip an image horizontally means that each row of the image is reversed.
[1,1,0] horizontally results in [0,1,1].To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0.
[0,1,1] results in [1,0,0].Example 1:
Input: image = [[1,1,0],[1,0,1],[0,0,0]]
Output: 1,0,0],[0,1,0],[1,1,1
Explanation:
First reverse each row: 0,1,1],[1,0,1],[0,0,0.
Then, invert the image: 1,0,0],[0,1,0],[1,1,1
Example 2:
Input: image = [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
Output: 1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0
Explanation:
First reverse each row: 0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1.
Then invert the image: 1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0
Constraints:
n == image.lengthn == image[i].length1 <= n <= 20images[i][j] is either 0 or 1.| Constructor and Description |
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Solution() |
| Modifier and Type | Method and Description |
|---|---|
int[][] |
flipAndInvertImage(int[][] image) |
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