public class Solution extends Object
786 - K-th Smallest Prime Fraction.
Hard
You are given a sorted integer array arr containing 1 and prime numbers, where all the integers of arr are unique. You are also given an integer k.
For every i and j where 0 <= i < j < arr.length, we consider the fraction arr[i] / arr[j].
Return the kth smallest fraction considered. Return your answer as an array of integers of size 2, where answer[0] == arr[i] and answer[1] == arr[j].
Example 1:
Input: arr = [1,2,3,5], k = 3
Output: [2,5]
Explanation:
The fractions to be considered in sorted order are:
1/5, 1/3, 2/5, 1/2, 3/5, and 2/3.
The third fraction is 2/5.
Example 2:
Input: arr = [1,7], k = 1
Output: [1,7]
Constraints:
2 <= arr.length <= 10001 <= arr[i] <= 3 * 104arr[0] == 1arr[i] is a prime number for i > 0.arr are unique and sorted in strictly increasing order.1 <= k <= arr.length * (arr.length - 1) / 2| Constructor and Description |
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Solution() |
| Modifier and Type | Method and Description |
|---|---|
int[] |
kthSmallestPrimeFraction(int[] arr,
int k) |
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