g1101_1200.s1111_maximum_nesting_depth_of_two_valid_parentheses_strings

Class Solution

java.lang.Object

g1101_1200.s1111_maximum_nesting_depth_of_two_valid_parentheses_strings.Solution

public class Solution
extends Object

1111 - Maximum Nesting Depth of Two Valid Parentheses Strings.

Medium

A string is a valid parentheses string (denoted VPS) if and only if it consists of "(" and ")" characters only, and:

• It is the empty string, or
• It can be written as AB (A concatenated with B), where A and B are VPS’s, or
• It can be written as (A), where A is a VPS.

We can similarly define the nesting depth depth(S) of any VPS S as follows:

• depth("") = 0
• depth(A + B) = max(depth(A), depth(B)), where A and B are VPS’s
• depth("(" + A + ")") = 1 + depth(A), where A is a VPS.

For example, "", "()()", and "()(()())" are VPS’s (with nesting depths 0, 1, and 2), and ")(" and "(()" are not VPS’s.

Given a VPS seq, split it into two disjoint subsequences A and B, such that A and B are VPS’s (and A.length + B.length = seq.length).

Now choose any such A and B such that max(depth(A), depth(B)) is the minimum possible value.

Return an answer array (of length seq.length) that encodes such a choice of A and B: answer[i] = 0 if seq[i] is part of A, else answer[i] = 1. Note that even though multiple answers may exist, you may return any of them.

Example 1:

Input: seq = “(()())”

Output: [0,1,1,1,1,0]

Example 2:

Input: seq = “()(())()”

Output: [0,0,0,1,1,0,1,1]

Constraints:

• 1 <= seq.size <= 10000

Constructor Summary

Constructors

Constructor and Description
Solution()

Method Summary

Modifier and Type	Method and Description
int[]	maxDepthAfterSplit(String seq)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail

Solution

public Solution()

Method Detail

maxDepthAfterSplit

public int[] maxDepthAfterSplit(String seq)