g1101_1200.s1190_reverse_substrings_between_each_pair_of_parentheses

Class Solution

java.lang.Object

g1101_1200.s1190_reverse_substrings_between_each_pair_of_parentheses.Solution

public class Solution
extends Object

1190 - Reverse Substrings Between Each Pair of Parentheses.

Medium

You are given a string s that consists of lower case English letters and brackets.

Reverse the strings in each pair of matching parentheses, starting from the innermost one.

Your result should not contain any brackets.

Example 1:

Input: s = “(abcd)”

Output: “dcba”

Example 2:

Input: s = “(u(love)i)”

Output: “iloveu”

Explanation: The substring “love” is reversed first, then the whole string is reversed.

Example 3:

Input: s = “(ed(et(oc))el)”

Output: “leetcode”

Explanation: First, we reverse the substring “oc”, then “etco”, and finally, the whole string.

Constraints:

• 1 <= s.length <= 2000
• s only contains lower case English characters and parentheses.
• It is guaranteed that all parentheses are balanced.

Constructor Summary

Constructors

Constructor and Description
Solution()

Method Summary

Modifier and Type	Method and Description
String	reverseParentheses(String s)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail

Solution

public Solution()

Method Detail

reverseParentheses

public String reverseParentheses(String s)