Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    1802 - Maximum Value at a Given Index in a Bounded Array\.

    Medium

    You are given three positive integers: n, index, and maxSum. You want to construct an array nums ( 0-indexed ) that satisfies the following conditions:

    • nums.length == n

    • nums[i] is a positive integer where 0 <= i < n.

    • abs(nums[i] - nums[i+1]) <= 1 where 0 <= i < n-1.

    • The sum of all the elements of nums does not exceed maxSum.

    • nums[index] is maximized.

    Return nums[index] of the constructed array.

    Note that abs(x) equals x if x >= 0, and -x otherwise.

    Example 1:

    Input: n = 4, index = 2, maxSum = 6

    Output: 2

    Explanation: nums = 1,2, **2** ,1 is one array that satisfies all the conditions. There are no arrays that satisfy all the conditions and have nums2 == 3, so 2 is the maximum nums2.

    Example 2:

    Input: n = 6, index = 1, maxSum = 10

    Output: 3

    Constraints:

    • <code>1 <= n <= maxSum <= 10<sup>9</sup></code>

    • 0 &lt;= index &lt; n

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer maxValue(Integer n, Integer index, Integer maxSum)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait