Class Solution
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public final class Solution2060 - Check if an Original String Exists Given Two Encoded Strings\.
Hard
An original string, consisting of lowercase English letters, can be encoded by the following steps:
Arbitrarily split it into a sequence of some number of non-empty substrings.
Arbitrarily choose some elements (possibly none) of the sequence, and replace each with its length (as a numeric string).
Concatenate the sequence as the encoded string.
For example, one way to encode an original string
"abcdefghijklmnop"might be:Split it as a sequence:
["ab", "cdefghijklmn", "o", "p"].Choose the second and third elements to be replaced by their lengths, respectively. The sequence becomes
["ab", "12", "1", "p"].Concatenate the elements of the sequence to get the encoded string:
"ab121p".
Given two encoded strings
s1ands2, consisting of lowercase English letters and digits1-9(inclusive), returntrueif there exists an original string that could be encoded as boths1ands2. Otherwise, returnfalse.Note: The test cases are generated such that the number of consecutive digits in
s1ands2does not exceed3.Example 1:
Input: s1 = "internationalization", s2 = "i18n"
Output: true
Explanation: It is possible that "internationalization" was the original string.
"internationalization"
-> Split: "internationalization"
-> Do not replace any element
-> Concatenate: "internationalization", which is s1.
"internationalization"
-> Split: "i", "nternationalizatio", "n"
-> Replace: "i", "18", "n"
-> Concatenate: "i18n", which is s2
Example 2:
Input: s1 = "l123e", s2 = "44"
Output: true
Explanation: It is possible that "leetcode" was the original string.
"leetcode"
-> Split: "l", "e", "et", "cod", "e"
-> Replace: "l", "1", "2", "3", "e"
-> Concatenate: "l123e", which is s1.
"leetcode"
-> Split: "leet", "code"
-> Replace: "4", "4"
-> Concatenate: "44", which is s2.
Example 3:
Input: s1 = "a5b", s2 = "c5b"
Output: false
Explanation: It is impossible.
The original string encoded as s1 must start with the letter 'a'.
The original string encoded as s2 must start with the letter 'c'.
Constraints:
1 <= s1.length, s2.length <= 40s1ands2consist of digits1-9(inclusive), and lowercase English letters only.The number of consecutive digits in
s1ands2does not exceed3.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final BooleanpossiblyEquals(String s1, String s2)-
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Method Detail
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possiblyEquals
final Boolean possiblyEquals(String s1, String s2)
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