Class Solution
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public final class Solution2223 - Sum of Scores of Built Strings\.
Hard
You are building a string
sof lengthnone character at a time, prepending each new character to the front of the string. The strings are labeled from1ton, where the string with lengthiis labeled <code>s<sub>i</sub></code>.For example, for
s = "abaca", <code>s<sub>1</sub> == "a"</code>, <code>s<sub>2</sub> == "ca"</code>, <code>s<sub>3</sub> == "aca"</code>, etc.
The score of <code>s<sub>i</sub></code> is the length of the longest common prefix between <code>s<sub>i</sub></code> and <code>s<sub>n</sub></code> (Note that <code>s == s<sub>n</sub></code>).
Given the final string
s, return the sum of the score of every <code>s<sub>i</sub></code>.Example 1:
Input: s = "babab"
Output: 9
Explanation: For s<sub>1</sub> == "b", the longest common prefix is "b" which has a score of 1.
For s<sub>2</sub> == "ab", there is no common prefix so the score is 0.
For s<sub>3</sub> == "bab", the longest common prefix is "bab" which has a score of 3.
For s<sub>4</sub> == "abab", there is no common prefix so the score is 0.
For s<sub>5</sub> == "babab", the longest common prefix is "babab" which has a score of 5.
The sum of the scores is 1 + 0 + 3 + 0 + 5 = 9, so we return 9.
Example 2:
Input: s = "azbazbzaz"
Output: 14
Explanation:
For s<sub>2</sub> == "az", the longest common prefix is "az" which has a score of 2.
For s<sub>6</sub> == "azbzaz", the longest common prefix is "azb" which has a score of 3.
For s<sub>9</sub> == "azbazbzaz", the longest common prefix is "azbazbzaz" which has a score of 9.
For all other s<sub>i</sub>, the score is 0.
The sum of the scores is 2 + 3 + 9 = 14, so we return 14.
Constraints:
<code>1 <= s.length <= 10<sup>5</sup></code>
sconsists of lowercase English letters.
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Constructor Summary
Constructors Constructor Description Solution()
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