Package g2501_2600.s2580_count_ways_to_group_overlapping_ranges

Class Solution

  • All Implemented Interfaces:
    
public final class Solution

    2580 - Count Ways to Group Overlapping Ranges\.

    Medium

    You are given a 2D integer array ranges where <code>rangesi = start<sub>i</sub>, end<sub>i</sub></code> denotes that all integers between <code>start<sub>i</sub></code> and <code>end<sub>i</sub></code> (both inclusive ) are contained in the <code>i<sup>th</sup></code> range.

    You are to split ranges into two (possibly empty) groups such that:

    • Each range belongs to exactly one group.

    • Any two overlapping ranges must belong to the same group.

    Two ranges are said to be overlapping if there exists at least one integer that is present in both ranges.

    • For example, [1, 3] and [2, 5] are overlapping because 2 and 3 occur in both ranges.

    Return the total number of ways to split ranges into two groups. Since the answer may be very large, return it modulo <code>10<sup>9</sup> + 7</code>.

    Example 1:

    Input: ranges = \[\[6,10],5,15]

    Output: 2

    Explanation:

    The two ranges are overlapping, so they must be in the same group.

    Thus, there are two possible ways:

    • Put both the ranges together in group 1.

    • Put both the ranges together in group 2.

    Example 2:

    Input: ranges = \[\[1,3],10,20,2,5,4,8]

    Output: 4

    Explanation:

    Ranges 1,3, and 2,5 are overlapping. So, they must be in the same group.

    Again, ranges 2,5 and 4,8 are also overlapping. So, they must also be in the same group.

    Thus, there are four possible ways to group them:

    • All the ranges in group 1.

    • All the ranges in group 2.

    • Ranges 1,3, 2,5, and 4,8 in group 1 and 10,20 in group 2.

    • Ranges 1,3, 2,5, and 4,8 in group 2 and 10,20 in group 1.

    Constraints:

    • <code>1 <= ranges.length <= 10<sup>5</sup></code>

    • ranges[i].length == 2

    • <code>0 <= start<sub>i</sub><= end<sub>i</sub><= 10<sup>9</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
      public class Solution.Companion

    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()

    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description

    • Method Summary

      Modifier and Type Method Description
      final Integer countWays(Array<IntArray> ranges)

      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait