Class Solution
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public final class Solution1217 - Minimum Cost to Move Chips to The Same Position.
Easy
We have
nchips, where the position of the <code>i<sup>th</sup></code> chip isposition[i].We need to move all the chips to the same position. In one step, we can change the position of the <code>i<sup>th</sup></code> chip from
position[i]to:position[i] + 2orposition[i] - 2withcost = 0.position[i] + 1orposition[i] - 1withcost = 1.
Return the minimum cost needed to move all the chips to the same position.
Example 1:
Input: position = 1,2,3
Output: 1
Explanation: First step: Move the chip at position 3 to position 1 with cost = 0. Second step: Move the chip at position 2 to position 1 with cost = 1. Total cost is 1.
Example 2:
Input: position = 2,2,2,3,3
Output: 2
Explanation: We can move the two chips at position 3 to position 2. Each move has cost = 1. The total cost = 2.
Example 3:
Input: position = 1,1000000000
Output: 1
Constraints:
1 <= position.length <= 1001 <= position[i] <= 10^9
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntegerminCostToMoveChips(IntArray position)-
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Method Detail
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minCostToMoveChips
final Integer minCostToMoveChips(IntArray position)
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