Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    1283 - Find the Smallest Divisor Given a Threshold.

    Medium

    Given an array of integers nums and an integer threshold, we will choose a positive integer divisor, divide all the array by it, and sum the division's result. Find the smallest divisor such that the result mentioned above is less than or equal to threshold.

    Each result of the division is rounded to the nearest integer greater than or equal to that element. (For example: 7/3 = 3 and 10/2 = 5).

    The test cases are generated so that there will be an answer.

    Example 1:

    Input: nums = 1,2,5,9, threshold = 6

    Output: 5

    Explanation: We can get a sum to 17 (1+2+5+9) if the divisor is 1. If the divisor is 4 we can get a sum of 7 (1+1+2+3) and if the divisor is 5 the sum will be 5 (1+1+1+2).

    Example 2:

    Input: nums = 44,22,33,11,1, threshold = 5

    Output: 44

    Constraints:

    • <code>1 <= nums.length <= 5 * 10<sup>4</sup></code>

    • <code>1 <= numsi<= 10<sup>6</sup></code>

    • <code>nums.length <= threshold <= 10<sup>6</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer smallestDivisor(IntArray nums, Integer threshold)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait