Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    1752 - Check if Array Is Sorted and Rotated.

    Easy

    Given an array nums, return true if the array was originally sorted in non-decreasing order, then rotated some number of positions (including zero). Otherwise, return false.

    There may be duplicates in the original array.

    Note: An array A rotated by x positions results in an array B of the same length such that A[i] == B[(i+x) % A.length], where % is the modulo operation.

    Example 1:

    Input: nums = 3,4,5,1,2

    Output: true

    Explanation: 1,2,3,4,5 is the original sorted array. You can rotate the array by x = 3 positions to begin on the the element of value 3: 3,4,5,1,2.

    Example 2:

    Input: nums = 2,1,3,4

    Output: false

    Explanation: There is no sorted array once rotated that can make nums.

    Example 3:

    Input: nums = 1,2,3

    Output: true

    Explanation: 1,2,3 is the original sorted array. You can rotate the array by x = 0 positions (i.e. no rotation) to make nums.

    Constraints:

    • 1 <= nums.length <= 100

    • 1 <= nums[i] <= 100

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Boolean check(IntArray nums)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait