2011 - Final Value of Variable After Performing Operations.

Easy

There is a programming language with only four operations and one variable X:

• ++X and X++ increments the value of the variable X by 1.

• --X and X-- decrements the value of the variable X by 1.

Initially, the value of X is 0.

Given an array of strings operations containing a list of operations, return the final value of X after performing all the operations.

Example 1:

Input: operations = "--X","X++","X++"

Output: 1

Explanation: The operations are performed as follows:

Initially, X = 0.

--X: X is decremented by 1, X = 0 - 1 = -1.

X++: X is incremented by 1, X = -1 + 1 = 0.

X++: X is incremented by 1, X = 0 + 1 = 1.

Example 2:

Input: operations = "++X","++X","X++"

Output: 3

Explanation: The operations are performed as follows:

Initially, X = 0.

++X: X is incremented by 1, X = 0 + 1 = 1.

++X: X is incremented by 1, X = 1 + 1 = 2.

X++: X is incremented by 1, X = 2 + 1 = 3.

Example 3:

Input: operations = "X++","++X","--X","X--"

Output: 0

Explanation: The operations are performed as follows:

Initially, X = 0.

X++: X is incremented by 1, X = 0 + 1 = 1.

++X: X is incremented by 1, X = 1 + 1 = 2.

--X: X is decremented by 1, X = 2 - 1 = 1.

X--: X is decremented by 1, X = 1 - 1 = 0.

Constraints:

• 1 <= operations.length <= 100

• operations[i] will be either "++X", "X++", "--X", or "X--".