Class Solution
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public final class Solution2265 - Count Nodes Equal to Average of Subtree.
Medium
Given the
rootof a binary tree, return the number of nodes where the value of the node is equal to the average of the values in its subtree.Note:
The average of
nelements is the sum of thenelements divided bynand rounded down to the nearest integer.A subtree of
rootis a tree consisting ofrootand all of its descendants.
Example 1:
Input: root = 4,8,5,0,1,null,6
Output: 5
Explanation:
For the node with value 4: The average of its subtree is (4 + 8 + 5 + 0 + 1 + 6) / 6 = 24 / 6 = 4.
For the node with value 5: The average of its subtree is (5 + 6) / 2 = 11 / 2 = 5.
For the node with value 0: The average of its subtree is 0 / 1 = 0.
For the node with value 1: The average of its subtree is 1 / 1 = 1.
For the node with value 6: The average of its subtree is 6 / 1 = 6.
Example 2:
Input: root = 1
Output: 1
Explanation: For the node with value 1: The average of its subtree is 1 / 1 = 1.
Constraints:
The number of nodes in the tree is in the range
[1, 1000].0 <= Node.val <= 1000
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntegeraverageOfSubtree(TreeNode root)-
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Method Detail
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averageOfSubtree
final Integer averageOfSubtree(TreeNode root)
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