PHP check variable function?

Question

I'm trying to write a function to check if my variables are valid. For example, in my script I have:

$flag = $_GET['page'];

But then I get the error:

Notice: Undefined index: page in C:\xampp\htdocs\phpinv\php\add.php on line 8

I tried writing a checkVar function:

function checkVar($var, $method, $defaultValue){
    if (!isset($method['$var'])) 
    {
        $var = $defaultValue;
    } else {
        $var = $method['$var'];
    }
}

But then I get:

Parse error: syntax error, unexpected '[' in C:\xampp\htdocs\phpinv\php\functions.php on line 21

Is that the whole body of the function? It seems pointless. $var is not a reference and yet the function is not returning anything. — Fad
– Fad, Commented Apr 15, 2012 at 9:04
the provided code has no line 21, so the parse error probably is outsie the function — Maxim Krizhanovsky
– Maxim Krizhanovsky, Commented Apr 15, 2012 at 9:05

F21 · Accepted Answer · 2012-04-15 09:04:02Z

1

Addressing '$var' in your array uses '$var' as a string and not the value stored in $var.

This is probably what you want:

function checkVar($var, $method, $defaultValue){ 
    if (!isset($method[$var]))  
    { 
        $var = $defaultValue; 
    } else { 
        $var = $method[$var]; 
    } 
}

answered Apr 15, 2012 at 9:04

F21

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Comments

Dhiraj · Accepted Answer · 2012-04-15 09:16:39Z

1

may be you should do something like this

    function checkVar($var, $method, $defaultValue){
        if (!isset($method[$var])) //instead of $method['$var']
        {
            $var = $defaultValue;
        } else {
            $var = $method[$var];
        }
        return $var;
    }

edited Apr 15, 2012 at 9:16

answered Apr 15, 2012 at 9:03

Dhiraj

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2 Comments

rgin Over a year ago

This and your checkVar function should be returning $var.

Dhiraj Over a year ago

well true, makes sense. Edited !

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