PHP Namespace Global

Question

Is there a way to get a PHP namespace to allow for calling functions within a namespace as if they were global?

Example:

handle()

Rather than:

prggmr\handle()

Here is my example code:

<?php
require_once 'prggmr/src/prggmr.php';

prggmr\handle(function() {
  echo 'This is a test scenario';
}, 'test');

prggmr\signal('test');

Aliasing does not work for functions:

<?php
require 'prggmr/src/prggmr.php';
use prggmr\handle;

handle(function(){
    echo "Test";
}, "test");

Results:

Fatal error: Call to undefined function handle()

Sasha · Accepted Answer · 2014-02-19 08:35:33Z

2

From my understanding this excerpt from the documentation says it's not possible ...

Neither functions nor constants can be imported via the use statement.

Source:

http://www.php.net/manual/en/language.namespaces.faq.php#language.namespaces.faq.nofuncconstantuse

edited Feb 19, 2014 at 8:35

Sasha

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answered Apr 19, 2012 at 17:16

Nick

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Comments

Jon · Accepted Answer · 2012-04-19 15:48:19Z

2

Not for a whole namespace, no. But for single names, you can do

use p\handle;

which aliases p\handle to just handle.

answered Apr 19, 2012 at 15:48

Jon

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1 Comment

JREAM Over a year ago

Hi thanks I have tried this. The thing is that the main file is namespaced: prggmr, this is giving me an undefined: ---- <?php use prggmr as p; use p\handle as handle; handle(function() {echo 1;}, 'hey'); signal('hey'); --- I have also tried \handle as a global but that wouldn't make sense.

miken32 · Accepted Answer · 2017-03-11 18:33:41Z

0

Thought I'd add an answer for modern PHP as I recently learned that:

Before PHP 5.6 neither functions nor constants can be imported via the use statement. As of PHP 5.6 aliasing or importing function and constant names is allowed.

So your second code sample should work just fine these days.

Also worth mentioning that you can define a block scope for PHP namespaces, though it's discouraged. So this would work:

<?php
require_once 'prggmr/src/prggmr.php';

namespace prggmr {
    handle(function() {
      echo 'This is a test scenario';
    }, 'test');

    signal('test');
}

answered Mar 11, 2017 at 18:33

miken32

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