Password Validation using hibernate bean validation

Question

I am trying to validate user input password against set of rules and here are those rules.

Minimum 6 and Maximum 8 Character.
Atleast 1 number
Atleast 1 alphabet in capitals.
No Special char allowed

this is what i have done so far in my bean class

@NotNull(message = "{register.pwd.invalid}")
    @Size(min = 6, max = 8, message = "{register.pwd.invalid}")
    public String getPwd()
    {
        return pwd;
    }

I believe for the rest part i have to use regExp but not sure what regular expression i need to have, this is what i came up

^.*(?=.{6,8})(?=.*\d)(?=.*[A-Z]).*$

i am not sure about the expression as i am not good in regExp,can any one help me to point in correcting the regExp

stema · Accepted Answer · 2012-06-04 07:24:01Z

2

You are quite close

^(?=.*\d)(?=.*[A-Z]).{6,8}$

Don't use .* at the start (it would sabotage the length check) and move the length check to the end.

answered Jun 4, 2012 at 7:24

stema

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Qtax · Accepted Answer · 2012-06-04 07:24:26Z

1

Remove the first .* and anchor the char limit, eg:

^(?=.*\d)(?=.*[A-Z]).{6,8}$

answered Jun 4, 2012 at 7:24

Qtax

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