Jquery function doesn't get parameter

Question

I'm using this function:

    $(function echo_content(name, content) {
        var random1 = Math.ceil(Math.random()*500);
        var random2 = Math.ceil(Math.random()*1000);
        alert(content);
        $('#TheDiv').show("slow");
});

And i'm calling this function on my webpage like this:

    <td>Content <script>echo_content("MyName", "The Content"); </script></td>

The problem is, that the function alerts undefined instead of The Content. What am I doing wrong?

VisioN · Accepted Answer · 2012-06-04 10:54:24Z

4

This is not a JQuery DOM ready handler. Just define your function like that:

function echo_content(name, content) {
    var random1 = Math.ceil(Math.random() * 500);
    var random2 = Math.ceil(Math.random() * 1000);
    alert(content);
    $("#TheDiv").show("slow");
}

BTW, #TheDiv block should be loaded before you call the function.

answered Jun 4, 2012 at 10:54

VisioN

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4 Comments

pangi Over a year ago

Your suggestion does not work. It doesn't show the alert. Am I doing something wrong?

pangi Over a year ago

Can you please tell me why this doesn't work: jsfiddle.net/DSgeb/2 ? My echo_content function is in scripts.js which is included into website. Thanks! :)

VisioN Over a year ago

@JernejPangeršič This doesn't work because your echo_content function is not defined in the scope. JSFiddle places the JS block to DOM ready handler. Use my example to get it work in JSFiddle. Check your scripts.js is included before you call the function.

pangi Over a year ago

How silly of me, I had scripts.js included afterwards :) Thank you very much! :)

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