Spring Hibernate JSP Insert Error

Question

I'm trying to insert into my database table, which I set up with hibernate/Spring, and I'm getting the following error

The class 'Layouts' does not have the property 'SubjectName'

The error is coming from the line

input type="text" name="SubjectName" size="50" value="${fn:escapeXml(layout.SubjectName)}"

but I clearly have SubjectName defined in my 'Layouts' model file as a String, and its in my hbm.xml file as

property name="SubjectName" type="string" column="SUBJECT"/

I also can't select form the database, although it's not giving an error. I feel like its coming from the same root problem

duffymo · Accepted Answer · 2012-06-04 22:17:34Z

1

Since Hibernate relies so much on convention, I'd check to make sure that the property name is "subjectName", not "SubjectName".

Java's coding conventions and Java Bean standards say that member names should start with a lower case character and provide getter/setter access. So private data member "foo" would have "getFoo" and "setFoo" methods.

Are you using Hibernate field or property access? I'd recommend field access.

answered Jun 4, 2012 at 22:17

duffymo

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2 Comments

yangdafish Over a year ago

Thanks, I changed all SubjectName to lowercase subjectName and the error actually went away. That's so ridiculous. Now its telling me that when I try to validate/save the data with ((LayoutManager)pageContext.getAttribute("layoutManager")).saveLayout((Layouts)pageContext.getAttribute("layout"))' that java.sql.SQLException: ORA-02289: sequence does not exist

duffymo Over a year ago

No, your failure to follow the conventions is ridiculous. Accept the answer - I'd prefer that to your thanks.

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