Encode JSON data into another JSON object

Question

I have a JSON string that I would like to include as a value in a larger JSON object that I am creating from an array. How can I create the larger JSON object without php escaping the string, and without having to decode the previously encoded string?

For example, if my JSON string is:

$encoded_already = '{"encoded_key": "encoded_value"}';

And I would like to include it in my array and json_encode() it:

$new_array = array(
    "some_other_key" => $some_value,
    "premade_data" => $encoded_already
);
$output = json_encode($new_array);

but I want to have the $encoded_already string be included as actual JSON, not just an escaped string.

jburns20 · Accepted Answer · 2012-06-22 03:12:04Z

2

Here's an idea: place a token as an attribute value and then use str_replace on it.

Works only if $token doesn't appear anywhere in your JSON.

$token = '%%%';
$output = str_replace( '"' . $token . '"', $encoded_already, json_encode( array(
    "some_other_key" => $some_value,
    "premade_data" => $token
) );

edited Jun 22, 2012 at 3:12

jburns20

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answered Jun 22, 2012 at 2:58

buley

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3 Comments

iambriansreed Over a year ago

Added $new_array =. :) You might want to replace '%%%' with uniqid().

jburns20 Over a year ago

OK, I was thinking about doing that but wasn't sure if there was a better way. That's going to be annoying with multiple strings though...

buley Over a year ago

sometimes dumb answers are the smart ones

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