Regex remove sequential duplicates from a space-delimited string

Question

I'm trying to remove (from a string) only the duplicates that occur sequentially. That is, given the string "1 2 3 3 2 1" only one of the 3's should be removed (i.e. "1 2 3 2 1"). I really thought I had it figured out. And then, during testing, I found a case where it didn't work. I've tried every combination I could think of, to no avail. Surely it's something simple, as it's not a hard match to do (except for me, obviously).

Following is some Javascript to illustrate the problem. The first testVal string is handled correctly. The commented-out testVal string is not handled correctly.

// The following string should reduce to: MTC MTCA MTC ORD MTC (it does).
var testVal = "MTC MTC MTCA MTC MTC MTC ORD MTC";

// The following string should reduce to: MTC (it does not.  Result = MTC MTC).
// The string MTC MTC MTC MTC also only reduces to MTC MTC, so I'm thinking
// it's a whitespace issue.
// var testVal = "MTC MTC";

while (/\b(\s*\w+\s*)\b\1/.test(testVal)) {
    testVal = testVal.replace(/\b(\s*\w+\s*)\b\1/g,'$1');
}

alert(testVal1);

Neil · Accepted Answer · 2012-07-12 23:35:27Z

1

You are including the whitespace as part of the word to be matched twice. Try

/\b(\w+)\s+\1\b/

answered Jul 12, 2012 at 23:35

Neil

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1 Comment

Brian Over a year ago

Sheesh. That was it. Thanks for the quick response @Neil!

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