jQuery ajax misunderstand functions

Question

I was reading something about Ajax and jQuery and I saw this code:

$.ajax({
  url: "test.html",
  cache: false
}).done(function( html ) {
  $("#results").append(html);
});

I don't see anywhere the declaration of "html", how will the code know what to append?

P.S. It might be a stupid question, but i didn't find the answer to this question anywhere :/

Kosmonaut · Accepted Answer · 2012-08-01 23:50:37Z

1

When the ajax call completes it will pass data into the function defined for done.

.done(function(html){

html is not "defined" here, but rather the name of the variable that receives the data. Once the placeholder is defined you can use it anywhere in your function.

For example, if you have

function myFunc(foo){
    alert(foo);
}

and then did

myFunc(1234);
//result 1234

myFunc("test");
//result "test"

So, really html is just what this person chose to call the data that is received from the ajax call. If you read the tutorial's on jQuery's site, most of the time they name this variable "data"

answered Aug 1, 2012 at 23:50

Kosmonaut

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2 Comments

Denn Over a year ago

So in the php file i have to call a var "html"? In example, if i have $data = "Hello World!" the ajax code will return "Hello World", right?

Kosmonaut Over a year ago

PHP cannot talk to javascript directly because it is processed in client side in the browsers whereas PHP is processed server side. If you have a php page called test.php with the code <% echo 'Hello World" %> the javascript variable "html" would contain "Hello World" with a successful response.

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