Python: Finding the value of a character in a string

Question

Given a long string such as:

"fkjdlfjzgjkdsheiwqueqpwnvkasdakpp"

or

"0.53489082304804918409853091868095809846545421135498495431231"

How do I find the value of the nth character in that string? I could solve this if I could convert it into a list (where each digit gets it's own index) but since the numbers aren't separated by commas I don't know how to do this either.

AFAIK there is no command like string.index(10) which would return the 11th character in.

Strings are indexable just like lists. myString[5] will return the 6th character. Also, if for some reason you wanted to make it into a list anyways, list(myString) will make a list in the way you mention. — Josiah
– Josiah, Commented Aug 7, 2012 at 10:02
You should work your way through the Python Tutorial docs.python.org/tutorial as it answers a lot of these questions. In particular docs.python.org/tutorial/introduction.html#strings will tell you all about subscripting and slicing strings. — Duncan
– Duncan, Commented Aug 7, 2012 at 10:20
also: my_str.index('c') is a method which will find the index of a substring. — jamylak
– jamylak, Commented Aug 7, 2012 at 10:26

Inbar Rose · Accepted Answer · 2012-08-07 10:06:20Z

29

strings are like lists. so you can access them the same way,

>>> a = "fkjdlfjzgjkdsheiwqueqpwnvkasdakpp"
>>> print a[10]
k

answered Aug 7, 2012 at 10:06

Inbar Rose

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sloth · Accepted Answer · 2012-08-07 10:04:33Z

5

Strings are iterable and indexable (since it is a sequence type), so you can just use:

"fkjdlfjzgjkdsheiwqueqpwnvkasdakpp"[10]

answered Aug 7, 2012 at 10:04

sloth

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Richie Bendall · Accepted Answer · 2018-12-14 05:09:02Z

2

To get the corresponding character in the nth value, just use this function:

def getchar(string, n):
    return str(string)[n - 1]

Example usage:

>>> getchar('Hello World', 5)
'o'

edited Dec 14, 2018 at 5:09

answered Nov 10, 2017 at 6:39

Richie Bendall

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