For the code below:
double j1;
j1=7000000 //example
ItemE[5]=[NSString stringWithFormat:@"@1. total inc = %g", j1];
ItemE[5] is returned as "1.total inc = 7e +06"
How do I prevent the scientific notation and have "1.total inc = 7000000" instead?
Use %f:
ItemE[5]=[NSString stringWithFormat:@"@1. total inc = %f", j1];
Edit:
If you don't want decimal places you should use:
ItemE[5]=[NSString stringWithFormat:@"@1. total inc = %.f", j1];
To elaborate, you were using wrong specifier in format string.%g instructs to create string representation of floating-point variable in scientific notation. Normally you should use %f to represent double and float variable. By default, this specifier will result in number with 6 decimal places. In order to change that you can modify that specifier, for example:
%5.3f means that string should have 3 decimal places and should be 5 characters long. That means that if representation would be shorter than 5 chars, string will have additional spaces in front of number to give 5 chars total. Note that if you will have large number, it'll not be truncated. Consider code:
double pi = 3.14159265358979323846264338327950288;
NSLog(@"%f", pi);
NSLog(@"%.3f", pi);
NSLog(@"%8.3f", pi);
NSLog(@"%8f", pi);
NSLog(@"%.f", pi);
will give result:
3.141593
3.142
3.142
3.141593
3
stringWithFormat: have a link to a “String Format Specifiers” page.
please, try to use this one:
double j1 = 7000000.f;
NSLog(@"1. total inc = %.f", j1);
the result will be:
1. total inc = 7000000
I hope it helps.
