I need to generate a big array (or list) with random numbers ( 10⁵ numbers) . I was trying like that:
vet = random.sample(range(10),100000)
But when I try to run :
vet = random.sample(range(10),10000)
File "/usr/lib/python2.7/random.py", line 320, in sample raise ValueError("sample larger than population") ValueError: sample larger than population
Any solution?
tkns
What you want is
[random.random() for _ in xrange(100000)]
From the random module documentation:
random.sample(population, k) Return a k length list of unique elements chosen from the population sequence. Used for random sampling without replacement.
so when calling random.sample(range(10), 100000) you're trying to extract 100000 unique elements in a sequence of length 10 which obviously can't work.
Note that
random.random() returns a floating value between [0 ; 1)random.randrange([start], stop[, step]) returns a random element from the sequence range([start], stop[, step])random.randint(a, b) returns an integer value in [a ; b]random.sample, the equality len(population) >= k must hold
xrange (which was just a "lazy" range) is now simply range. See e.g. stackoverflow.com/questions/15014310/….I think you're after something like this:
vet = [random.randint(1,10) for _ in range(100000)]
You can you the numpy function and create an array with N space filled with a random number
import numpy as np
vector_size = 10000
one_dimensional_array = np.random.rand(vector_size)
two_dimensional_array = np.random.rand(vector_size, 2)
tree_dimensional_array = np.random.rand(vector_size, 3)
#and so on
You can create matrix of random numbers using the function below and arrays also.
import numpy; vet = numpy.random.randint(0, 10, 10000)