Java and If statement

Question

Can anyone tell me if im doing something wrong ?

public class Jafntekkijafnt
{
    public static void main(String[] args)
    {
        int a = Integer.parseInt(args[0]);
        int b = Integer.parseInt(args[1]);
        int c = Integer.parseInt(args[2]);
        if (a == b) (b == c) (c == a)   System.out.println("equal");
        else                            System.out.println("not equal");
    }
}

It's java programming
I'm trying create a program with three integers that prints equal if all are equal and not equal if they are not.

I know its the 8th line but don't how to get it right.

Looks like line 8 is invisible (like the rest of your code). — John3136
– John3136, Commented Sep 5, 2012 at 14:30
Using if(args[0].equals(args[1]) && args[1].equals(args[2])) may be all you need. — Peter Lawrey
– Peter Lawrey, Commented Sep 5, 2012 at 14:34

gefei · Accepted Answer · 2012-09-05 14:29:58Z

10

instead of if (a==b)(b==c)(c==a) use

if (a==b && b==c)

Note there is no need to write c==a if a==b and b==c hold

answered Sep 5, 2012 at 14:29

gefei

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2 Comments

The Cat Over a year ago

I think equals is transitive.

Boris Treukhov Over a year ago

@TheCat Yes, equals() is transitive(it's specified in its java doc) Interesting though - I can't find anything about == transitivity in the JLS specification so I'm feeling a bit foolish )))

RNJ · Accepted Answer · 2012-09-05 14:30:29Z

0

THere is a problem with your "if" syntax. It should be

if (a == b && b == c && c == a) {
//...
}

Note that youare using primitives here and not object. If you were using Integer instead of int then the == would check if the objects were teh same and not if there values were the same. In this case you would need to use

if (a.equals(b) && b.equals(c) && c.equals(a)) {
//...
}

The && means logical and and is explained here

answered Sep 5, 2012 at 14:30

RNJ

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Comments

The Cat · Accepted Answer · 2012-09-05 14:30:34Z

0

You have got the brackets a little bit wrong and you need to use the AND (&&) operator.

answered Sep 5, 2012 at 14:30

The Cat

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Comments

Derek W · Accepted Answer · 2012-09-05 15:02:51Z

Not that it is strictly necessary in the one-line case, but you should also include brackets around your 'if' and 'else' statements. It's bad practice not to use them because it can lead to some unsuspected behavior. I know personally that I've gotten burned in the past over this issue. Plus it makes your code easier to read which is invaluable.

My code is below:

public class ThreeIntTest {
public static void main(String[] args) {
    int a = Integer.parseInt(args[0]);
    int b = Integer.parseInt(args[1]);
    int c = Integer.parseInt(args[2]);
    if ((a == b) && (b == c)) {
        System.out.println("The three integers are equal.");
    } else {
        System.out.println("The three integers are not equal.");
    }
} }

The && logical operator will tell the 'if statement' if both a==b AND b==c evaluate as true, if one or both are not true, then the statement is made false and you go directly to your 'else statement.'

Used here is the transitivity property of relations. Which says that if a = b and b = c, then it follows that a = c. This is the most effective way that I can think of comparing three integers.

nick · Accepted Answer · 2012-09-05 15:12:00Z

0

Try this:

if(a == b && a == c && b == a && b == c && c == a && c == b){
...
}

Quick and easy.

answered Sep 5, 2012 at 15:12

nick

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Comments

Zoltan Toth · Accepted Answer · 2012-09-05 16:37:26Z

0

You need to use && between the brackets () :

(a==b) && (b==c) && (c==a)

edited Sep 5, 2012 at 16:37

Zoltan Toth

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answered Sep 5, 2012 at 14:33

Bourkadi

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