How do I check every value in a Java string?

Question

If I had a string, say:

String name;

Is there a way I can check each letter with a loop? So if they enter a name can I check what each letter is?

Despite the number of answers, it's really not clear what you're asking here. I suggest you expand your question, what are you trying to do? Validate the string? Blacklist particular characters? — EdC
– EdC, Commented Sep 16, 2012 at 10:17

Sergey Kalinichenko · Accepted Answer · 2012-09-16 10:15:49Z

6

There are several ways to do it - you can do a for loop with an index, or a foreach loop on the char[] array:

for (int i = 0 ; i != s.length() ; i++) {
    char c = s.charAt(i);
    ....
}

for (char c : s.toCharArray()) {
    ....
}

In addition to checking each letter separately, you can check all letters at once (or any subset that you'd like) with regular expressions.

answered Sep 16, 2012 at 10:15

Sergey Kalinichenko

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Comments

Makoto · Accepted Answer · 2012-09-16 21:57:24Z

3

Use the String.toCharArray() function.

edited Sep 16, 2012 at 21:57

Makoto

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answered Sep 16, 2012 at 10:12

elyashiv

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Comments

Makoto · Accepted Answer · 2012-09-16 21:57:55Z

2

char[] chars = name.toCharArray();
for (int i =0; i < chars.length; i++)
{
    System.out.println(chars[i]);
}

edited Sep 16, 2012 at 21:57

Makoto

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answered Sep 16, 2012 at 10:13

Thousand

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1 Comment

Peter Lawrey Over a year ago

or for(char ch: name.toCharArray())

xeon111 · Accepted Answer · 2012-09-16 10:14:31Z

1

This should do

for ( int i=0 ; i < name.length(); i++)
{
   name.charAt(i);
}

Also read this http://docs.oracle.com/javase/tutorial/java/data/manipstrings.html

answered Sep 16, 2012 at 10:14

xeon111

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