base on my understanding, this how list() work.
list($A1,$A2,$A3) = array($B1,B2,B3);
So with the help of list() we can assign value out from array accordingly.
here is my question... how to generate a dynamic list()?
1). base on database return result, I'm not sure how many of it but I assign it all into array
2). so we can use count(array) to know how many of it.
3). so then HOW CAN I GENERATE/PREPARE a list for it?
Example: client A, have 3 kids, name Apple, Boy, Cat
so I use list($kid1, $kid2, $kid3) for it.
but when client B, have more then 3 kids, I only get first 3 or if client C, have only 1 kids, then error encounter.
I know if base on the situation above, there is many way to solve it without using list()
but I wish to know or find out the solution with using list().
How to generate dynamic list() base on count of array()
thanks guys/gals
list? Why not simply access them by their index? There seems to be no gain by usinglistin this case...i know if base on the situation above, there is many way to solve it without using list() but i wish to know or find out the solution with using list().from questionextract()on the array, to create variables inside the current scope...