Displaying Binary of Each Character in a String

Question

I have figured out how to get user's input (string) and take each letter from them and give a binary equivalent of each letter.

The problem is I want each letter to give a binary number by having one letter per line when displaying on screen. I would like help in doing so.

For example:

C 0 1 0 0 0 0 1 1
h 0 1 1 0 1 0 0 0
a 0 1 1 0 0 0 0 1
n 0 1 1 0 1 1 1 0
g 0 1 1 0 0 1 1 1

This is the code I used:

#include <stdio.h>

int main()
{

    //get input
    printf( "Enter a string: " );
    char s[255];
    scanf( "%[^\n]s" , s );

    //print output 
    printf( "'%s' converted to binary is: " , s );

    //for each character, print it's binary aoutput
    int i,c,power;

    for( i=0 ; s[i]!='\0' ; i++ )
    {
        //c holds the character being converted
        c = s[i];

        //for each binary value below 256 (because ascii values < 256)
        for( power=7 ; power+1 ; power-- )
        //if c is greater than or equal to it, it is a 1
        if( c >= (1<<power) )
        {
            c -= (1<<power); //subtract that binary value
            printf("1");
        }
        //otherwise, it is a zero
        else
            printf("0");
    } 

    return 0;
}

You're doing all the hard work already, I don't see where your problem is — Asciiom
– Asciiom, Commented Sep 23, 2012 at 8:32

Raj · Accepted Answer · 2012-09-23 09:31:47Z

1

You just need to add a printf("\n") statement after you process each character.

for( i=0 ; s[i]!='\0' ; i++ )
    {
        //c holds the character being converted
        c = s[i];

        //for each binary value below 256 (because ascii values < 256)
        for( power=7 ; power+1 ; power-- )
        //if c is greater than or equal to it, it is a 1
        if( c >= (1<<power) )
        {
            c -= (1<<power); //subtract that binary value
            printf("1");
        }
        //otherwise, it is a zero
        else
            printf("0");

        /* Add the following statement, for this to work as you expected */
        printf("\n");
    }

answered Sep 23, 2012 at 9:31

Raj

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Comments

Asciiom · Accepted Answer · 2012-09-23 08:33:57Z

0

Instead of printing your 1and 0immediately, build a string from them. Then print out the character you just converted next to the string you just built.

answered Sep 23, 2012 at 8:33

Asciiom

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Comments

Christophe Biocca · Accepted Answer · 2012-09-23 08:34:46Z

0

To print each character on a new line, print a newline after printing each character:

printf("\n");

To print the character first, use putchar:

putchar(c);

answered Sep 23, 2012 at 8:34

Christophe Biocca

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Comments

epsalon · Accepted Answer · 2012-09-23 08:35:22Z

0

Setting aside the bad code style, it seems what you are looking for is a simple

printf("\n");

statement immediately following the printf("0"); in the end of the outer for loop to add newlines.

answered Sep 23, 2012 at 8:35

epsalon

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