Turn JSON script URL into variables in PHP

Question

I was wondering how on earth to get a json string into php.. here's my string:

(go here) http://urls.api.twitter.com/1/urls/count.json?url=http://www.onewiththem.com.au/&callback=twttr.receiveCount

and you should see this returned:

twttr.receiveCount({"count":0,"url":"http:\/\/www.onewiththem.com.au\/"});

I was wondering how to get the count number and have it set up in the variable $count ?

First of all, remove &callback=. Are you asking for a JSON parser? — SLaks
– SLaks, Commented Oct 3, 2012 at 2:16
use json_decode() php.net/manual/en/function.json-decode.php — Virendra
– Virendra, Commented Oct 3, 2012 at 2:18

Ja͢ck · Accepted Answer · 2012-10-03 02:17:58Z

2

Simple, using json_decode() and file_get_contents():

$data = json_decode(file_get_contents('http://urls.api.twitter.com/1/urls/count.json?url=http://www.onewiththem.com.au/'));
echo $data->count;

Note that I removed the &callback= from the URL, because that's only used for JSONP and PHP doesn't need it.

answered Oct 3, 2012 at 2:17

Ja͢ck

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xdazz · Accepted Answer · 2012-10-03 02:17:06Z

0

If you mean get it in javascript, then the data in your callback function is the object. You could get the count just by data.count.

twttr.reciveCount = function (data) {
  console.log(data.count);
  // do the rest
}

If you call the api from php, then you should not use the callback parameter. Get the JSON response and then use json_decode to decode it. (Don't forget urlencode the url parameter.)

$response = file_get_contents('http://urls.api.twitter.com/1/urls/count.json?url='.urlencode('http://www.onewiththem.com.au/'));
$json = json_decode($response);
echo $json->count;

answered Oct 3, 2012 at 2:17

xdazz

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