Add variable in PHP

Question

I would like to change the location that a files uploads to by adding a PHP variable to the path name but I am unable to get it to work but I'm pretty sure it's a syntax error.

This doesn't work:

$this->options = array(
     'script_url' => $this->get_full_url().'/',
     'upload_dir' => dirname($_SERVER['SCRIPT_FILENAME']).'/'.$user.'/',
     'upload_url' => $this->get_full_url().'/'.$user.'/',
     'param_name' => 'files'
)

This does:

$this->options = array(
     'script_url' => $this->get_full_url().'/',
     'upload_dir' => dirname($_SERVER['SCRIPT_FILENAME']).'/bob/',
     'upload_url' => $this->get_full_url().'/bob/',
     'param_name' => 'files'
)

I realize that this is not the full code, but I wondered whether there is a simple syntax error I am missing here.

Nothing discernible here, assuming both statements close with a );... what comes above this code? That's probably where the syntax problem lies, but the parser doesn't find it until later on. — Patrick Moore
– Patrick Moore, Commented Oct 8, 2012 at 19:48
First and foremost always activate error displaying. error_reporting(E_ALL); ini_set('display_errors', TRUE); because obviously there is some kind of error there that is not show to you and you need to read the error message and start searching based on that. — Mihai Stancu
– Mihai Stancu, Commented Oct 8, 2012 at 19:53

Niet the Dark Absol · Accepted Answer · 2012-10-08 19:50:30Z

2

You don't appear to have defined $user anywhere. Even if you have, the code you gave seems to be part of a class declaration so you need to make sure $user is defined in the current scope (global $user if needed, or as a last resort try $GLOBALS['user']).

answered Oct 8, 2012 at 19:50

Niet the Dark Absol

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1 Comment

cmbuckley Over a year ago

If this is the case, I recommend reading the manual on variable scope.

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