converting string to date in php

Question

First i entered e6 = 24-09-2011 as input type = "text" in previous page then:

  $a6 = $_POST["e6"]   ; 
  $time = strtotime( $a6 );
  $myDate = date ("y-m-d", $time ); 
  echo $myDate ;
  $n = strtotime(date("Y-m-d", strtotime($myDate)) . " +$a7 month");
  $q = date("Y-m-d", $n);
  echo $q ;

out put: 11-09-24 2013-09-24

I want to print 2011 in place of only 11. What should I do ?? pls help.

just capitalize y in $myDate = date ("y-m-d", $time );

Bhuvan Rikka
– Bhuvan Rikka

2012-10-17 08:54:11 +00:00
Commented Oct 17, 2012 at 8:54 — Bhuvan Rikka
– Bhuvan Rikka, Commented Oct 17, 2012 at 8:54
If a user has given you the correct answer. Please accept.

RSM
– RSM

2012-11-07 11:22:11 +00:00
Commented Nov 7, 2012 at 11:22 — RSM
– RSM, Commented Nov 7, 2012 at 11:22

RSM · Accepted Answer · 2012-10-17 08:53:11Z

3

 $a6 = $_POST["e6"]   ; 
    $time = strtotime( $a6 );
    $myDate = date ("Y-m-d", $time ); 
    echo $myDate ;
    $n = strtotime(date("Y-m-d", strtotime($myDate)) . " +$a7 month");
    $q = date("Y-m-d", $n);
    echo $q ;

You needed to change all the lower case y to capital Y. See here.

answered Oct 17, 2012 at 8:53

RSM

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Comments

Flame · Accepted Answer · 2012-10-17 08:53:18Z

0

$myDate = date ("y-m-d", $time );
should be with a capital 'Y' like so :
$myDate = date ("Y-m-d", $time );

Php docs has a very good explanation on the data-string formatting: Here

answered Oct 17, 2012 at 8:53

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