JS: Append variable to URL without repeating [duplicate]

Question

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Change URL parameters with jQuery?

Currently, I have a <div> tag that looks like a button and changes the URL with an onClick function which redirect to the same page just adds &view_all=Yes or &view_all=No to the URL.

<div onclick="javascript:window.location.href = 'page.php?action=list-volunteer-apps&view-all=No';">Hide Closed Applications</div>

Well, I am adding a new feature to the website and I need to be able to append that &view_all=Yes or &view_all=No to the end of the URL instead of redirecting them because I'll have other variables in the URL that I can't lose.

I have figured out a way to do the append but it keeps adding the &view_all variables to the end of URL so it looks like this page.php?action=list-volunteer-apps&view-all=No&view_all=Yes&view_all=No.

This is the way I am doing the append: onclick="javascript:window.location.assign(window.location.href+='&view-all=No');"

Yes, of course I searched. Just used the wrong search query. Thank you. — Draven
– Draven, Commented Oct 23, 2012 at 8:06
@shiplu.mokadd.im Could you give me an example on how to use that to solve my problem? I don't know JS that well. — Draven
– Draven, Commented Oct 23, 2012 at 8:15
Using that function you can get an object or associated array of url parameters. After that you have to add/modify new value to view_all variable. Then build the new url. Its the opposite of that function. — Shiplu Mokaddim
– Shiplu Mokaddim, Commented Oct 23, 2012 at 8:22

VisioN · Accepted Answer · 2012-10-23 08:16:53Z

0

You can use regular expression to replace the value in a string:

$(this).attr("onclick", function(i, val) {
    return val.replace(/view-all=(Yes|No)/, function() {
        return "view-all=" + ((arguments[1] || "") == "Yes" ? "No" : "Yes");
    });
});

answered Oct 23, 2012 at 8:16

VisioN

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3 Comments

Draven Over a year ago

Could you tell me how I would use that exactly?

VisioN Over a year ago

@Draven For instance, like that: jsfiddle.net/mx7s8.

Draven Over a year ago

Well, seems like a good idea but I just don't know enough JS to get it to work.

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