Javascript reverse sorting

Question

i have a problem on javascript reverse method when all the data to be sorted are equal.

here is my code:

var ascAgt = false;
        function sortTableAgt() {
            var tbl = document.getElementById("mytable").tBodies[0];
            var store = [];
            for (var i = 0, len = tbl.rows.length; i < len; i++) {
                var row = tbl.rows[i];
                var rowdatedata = row.cells[1].innerHTML;
                store.push([rowdatedata, row]);
            }
            if (ascAgt) {
                store.sort();
                ascAgt = false;
            } else {
                store.sort();
                store.reverse();
                ascAgt = true;
            }
            for (var i = 0, len = store.length; i < len; i++) {
                var idno = i + 1;
                store[i][1].cells[0].innerHTML = idno.toString();
                tbl.appendChild(store[i][1]);
            } store = null;
        }

sample data:

ID  Name    Date
1   XXXXX   2012/10/05
2   XXXXX   2012/03/16
3   XXXXX   2012/05/18
4   XXXXX   2012/05/18

as i sort the name part,what i want is that nothing happens because names are equal but when it comes to the reverse method it will just reversed the given data. am i missing something here? thank you in advance....

How do you expect sort to work on an array containing arrays? Same with reverse. — Some Guy
– Some Guy, Commented Oct 25, 2012 at 12:49

geocodezip · Accepted Answer · 2018-12-13 02:42:19Z

So, what you want is to sort by 2nd column and, if the values are equal, sort also by 3rd column. Right?

The sort() function takes also a callback. You have to use that.

var ascAgt = false;

function sortTableAgt() {
  var table = document.getElementById("mytable").tBodies[0],
      rows = table.rows,
      len = rows.length,
      i = 0,
      store = [],
      order = ascAgt ? 1 : -1;

  for (i = 0; i < len; i++) {
    store.push(rows[i]);
  }

  store.sort(function(a, b) {
    if (a.cells[1].innerHTML == b.cells[1].innerHTML) {

      // If 2nd cell are equal, sort by 3rd cell
      // Compare them as date (timestamp)
      var dateA = new Date(a.cells[2].innerHTML).getTime(),
          dateB = new Date(b.cells[2].innerHTML).getTime();

      if (dateA == dateB) {
        return 0;
      } else if (dateA < dateB) {
        return -1 * order;
      } else {
        return 1 * order;
      }

    } else if (a.cells[1].innerHTML < b.cells[1].innerHTML) {
      return -1 * order;
    } else {
      return 1 * order;
    }
  });

  for (i = 0; i < len; i++) {
    store[i].cells[0].innerHTML = (i+1).toString();
    table.appendChild(store[i]);
  }
}

You can also check tis demo in JSBin: http://jsbin.com/welcome/39336/edit

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