a file contains informaton like below I'd like to covert this file into list of list of string There is a blank line between group.
pear
banana
milk
tea
coffee
and the result returns:
build_list(f):
[[pear, banana], [milk, tea, coffee]]
-
I am thinking about geting rid of the blank line between each group. But so far my code is not working.user1718467– user17184672012-11-11 05:57:30 +00:00Commented Nov 11, 2012 at 5:57
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3 Answers
This should do it:
with open("data.txt") as f:
res = [line.split('\n') for line in f.read().split('\n\n')]
Split the input data into groups then split each group into lines.
Comments
Try this:
from itertools import groupby
def build_list(name):
with open(name, "r") as f:
return [[i.strip() for i in group] for key, group in
groupby(f, key=lambda k: (k.strip() == "")) if not key]
This solution will even allow for degenerate files where you have more than one empty line between groups or multiple empty lines at the end.
Comments
Stack_13328928.txt is your list. Please note that the last line in your input file has to be a new line, otherwise the last item is lost, but I think the code can be modified that you don't need a blank new line.
import csv
in_file = open("stack_13328928.txt")
CSV = csv.reader(in_file)
outer_ls = []
inter_ls = []
for i in CSV:
try:
i[0]
inter_ls += i
except:
outer_ls.append(inter_ls)
inter_ls = []
print outer_ls
