The array count returns wrong answer in php

Question

This is my php code:

$allids_arr = $_REQUEST['allids'];
print_r($allids_arr);
echo $arr_count = count($allids_arr);

The array printed like this:

Array (
     [0] => 26 
     [1] => 27 
     [2] => 28 
     [3] => 29 
     [4] => 30 
     [5] => 31 
     [6] => 32 
     [7] => 33 
)

But the count display as 1.

But the correct answer is 8.

What is the problem in my code?

EDIT:

The array was i created: This is the code for my array creation:

$allids = array();
        $ikall = 0;
        foreach($alldata as $rwosall){
            $allids[$ikall] = $rwosall['journelmodel']['id'];
            $ikall++;
        }   
        $this->set('alldataids', $allids);

This is in my controller.And in my view page:

<input type="hidden" readonly="" id="allids" class="input1" name="allids" value="<?php print_r($alldataids);?>">

This value was i requested when form submitted.

Instead of echo $arr_count = count($allids_arr); just use echo count($allids_arr); — vivek salve
– vivek salve, Commented Nov 17, 2012 at 6:56
You must be doing something else in the code that you aren't showing us. Try putting echo count($_REQUEST['allids']); at the top of your script. Then put $allids_arr = $_REQUEST['allids']; right afterwards. Then put echo count($allids_arr); right after that. No reason that should not give you consistent output. Also please print_r($_REQUEST) to make sure you are doing that right. — Buttle Butkus
– Buttle Butkus, Commented Nov 17, 2012 at 7:26
@Kichu What exactly do you expect your <input..> field to do with output from print_r($array). That doesn't look like it'll work. — Anirudh Ramanathan
– Anirudh Ramanathan, Commented Nov 17, 2012 at 7:40
Cthulthu is right, that form will submit a single string formatted to look like an array. You need to either pack/unpack that data using, for example, JSON, or pass it in multiple inputs, one value per input. — user1233508
– user1233508, Commented Nov 17, 2012 at 7:42

som · Accepted Answer · 2012-11-17 08:09:42Z

2

First of all there are few mistakes in your code.

You assign array in hidden field using print_r function which is not an array.
When you submit the value and get the value using $_REQUEST which is treated as a string.It looks like array that is why count is returning 1.

Solution : 1. You can assign value as comma separated like "x,y,z"

answered Nov 17, 2012 at 8:09

som

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Comments

simon · Accepted Answer · 2012-11-17 06:55:16Z

0

you need:

echo count($allids_arr);

or

$arr_count = count($allids_arr);
echo $arr_count;

:)

answered Nov 17, 2012 at 6:55

simon

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6 Comments

nonopolarity Over a year ago

but I tried in my code to do a $foo = array("hi", 2, 8); echo $c = count($foo); and it does print 3

Anirudh Ramanathan Over a year ago

Actually his version should work as well. The return value from an assignment is the RHS.

Anirudh Ramanathan Over a year ago

@Kichu do echo count($allids_arr, 1); It will count recursively, in case some elements are nested deeper. Not sure

nonopolarity Over a year ago

@Kichu are you sure you didn't do anything in between printing of the array and printing the count? Can you somehow make it into 3 lines of self-contained code or so that will show this behavior?

Kichu Over a year ago

i cant understand your suggestion...do you mean to dont write it in 3 line of code is it?

|

Ankur Saxena · Accepted Answer · 2012-11-17 07:17:49Z

0

$_REQUEST, by default, contains the contents of $_GET, $_POST and $_COOKIE.

But it's only a default, which depends on variables_order ; and not sure you want to work with cookies.

If I had to choose, I would probably not use $_REQUEST, and I would choose $_GET or $_POST -- depending on what my application should do (i.e. one or the other, but not both) : generally speaking :

You should use `$_GET` when someone is requesting data from your application.
And you should use `$_POST` when someone is pushing (inserting or updating ; or deleting) data to your application.

Either way, there will not be much of a difference about performances : the difference will be negligible, compared to what the rest of your script will do.

answered Nov 17, 2012 at 7:17

Ankur Saxena

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2 Comments

Buttle Butkus Over a year ago

This would not explain the inconsistency in his output.

Ankur Saxena Over a year ago

print_r($allids_arr); echo $arr_count = count($allids_arr); //this code work fine.there must be default in somewhere $_REQUEST.use print_r($_REQUEST);

elp · Accepted Answer · 2012-11-17 07:34:11Z

0

Try use this:

<?php
    $foo = $_REQUEST['foo'];
    print_r($foo);
    echo $arr_count = count($foo);
?>

with this query:

sample.php?foo[]=test&foo[]=baz&foo[]=foo

It return correct result:

Array ( [0] => test [1] => baz [2] => foo ) 3

...probably if you use the same name for array and params, work well.

hope this help.

answered Nov 17, 2012 at 7:34

elp

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